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Natalka [10]
2 years ago
15

High-temperature superconducting oxides hold great promise in the utility, transportation, and computer industries.

Chemistry
1 answer:
koban [17]2 years ago
6 0

The main class of high-temperature superconductors are in the class of copper oxides (only some particular copper oxides) especially the Rare-earth barium copper oxides (REBCOs) such as Yttrium barium copper oxide (YBCO).

<h3>What superconducting material works with the highest temperature?</h3>

As of 2020, the material with the highest accepted superconducting temperature is an extremely pressurized carbonaceous sulfur hydride with a critical transition temperature of +15°C at 267 GPa.

<h3>How do high-temperature superconductors work?</h3>

High-temperature superconductivity, the ability of certain materials to conduct electricity with zero electrical resistance at temperatures above the boiling point of liquid nitrogen, was unexpectedly discovered in copper oxide (cuprate) materials in 1987.

Learn more about high temperature superconductors here:

<h3>brainly.com/question/1657823</h3><h3 /><h3>#SPJ4</h3>

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A reading shows a pressure measurement of 43 in. Hg. What is the equivalent pressure in psi? A. 5.73 psi B. 2223.13 psi C. 26.32
oksian1 [2.3K]
43 inHg = 43 inHg*2.54cm/in = 109.22cmHg * 10 mm/cm = 1092.2 mmHg


14.7 psi = 760 mmHg

1092.2mmHg * 14.7psi / 760 mmHg = 21.13 psi

Answer: option D. 21.13 psi
7 0
4 years ago
Read 2 more answers
Which product of prime polynomials is equivalent to 36x3 – 15x2 – 6x?
monitta
The product of prime polynomials is equivalent to 36x3 – 15x2 – 6x is letter B which is 3x(3x – 2)(4x 1). Below is the solution. 

3x(3x - 2) (4x + 1)
= 9x2 - 6x (4x + 1)
= 36x3 + 9x2 + -  24x2 - 6x
= 36x3 - 15x2 - 6x
       
3 0
3 years ago
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Details about outer ear
Verdich [7]
Outer ear is the is external part of the ear, consists of the auricle ( also pinna), and the ear canal. It gathers sound energy and focuses it on the ear drum.  
7 0
3 years ago
Cdvshduejsnxhhwjxhxh ydujdbxg
fiasKO [112]

Answer:

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Explanation:

5 0
3 years ago
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The pKb of the base cyclohexamine, C6H11NH2, is 3.36. What is the pKa of the conjugate acid, C6H11NH3
bonufazy [111]

Answer:

10.64

Explanation:

Let's consider the basic reaction of cyclohexamine, C₆H₁₁NH₂.

C₆H₁₁NH₂(aq) + H₂O(l) ⇄ C₆H₁₁NH₃⁺(aq) + OH⁻     pKb = 3.36

C₆H₁₁NH₃⁺ is its conjugate acid, since it donates H⁺ to form C₆H₁₁NH₂. C₆H₁₁NH₃⁺ acid reaction is as follows:

C₆H₁₁NH₃⁺(aq) + H₂O(l) ⇄ C₆H₁₁NH₂(aq) + H₃O⁺(aq)   pKa

We can find the pKa of C₆H₁₁NH₃⁺ using the following expression.

pKa + pKb = 14.00

pKa = 14.00 - pKb = 14.00 - 3.36 = 10.64

6 0
4 years ago
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