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sladkih [1.3K]
3 years ago
11

What are the soulutions to m^2-9=0

Mathematics
2 answers:
mihalych1998 [28]3 years ago
4 0

Answer:

m= 3, -3

Step-by-step explanation:

Hope this helps!

Mice21 [21]3 years ago
4 0
Answer : m=3 or m=-3
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What is the ratio of 65*3^17 to 65*3^14
solniwko [45]
<span>The ratio of 65*3^17 to 65*3^14 can be found as follows:

(65) (3^17)      65
--------------- = ----- * 3^(17-14) = 1 * 3^3 = 27 (answer)
(65) (3^14)      65</span>
3 0
3 years ago
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How would you solve 3x^2-12=0?
Gennadij [26K]

                                                                                 3x^2 - 12  =  0

Personally, I would divide each side by 3                x^2 - 4  =  0

Then I would add 4 to each side                              x^2        =  4

Then I would take the square root of each side:     x  =  +4
                                                                                     x  =  -4 .

Having found both solutions, I would relax with a cup of tea.

3 0
3 years ago
segment CD has endpoints at C(0, 3) and D(0, 7). If the segment is dilated by a factor of 3 about point C, what is the length of
zalisa [80]

The length of CD is 7-3=4.

Therefore, if we dilate by a scale factor of 3, the length is 4(3) = 12

5 0
2 years ago
What is the common difference for the sequence shown below?
Alex Ar [27]
It is B because for every point going down, there is 3 to the left and so it is 1/3 and it has to be negative because its going left
4 0
3 years ago
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Simplify 3(2m^3n^-2)^4
Effectus [21]

Answer:

(48 m^12)/n^8

Step-by-step explanation:

Simplify the following:

3 ((2 m^3)/(n^2))^4

Multiply each exponent in (2 m^3)/(n^2) by 4:

3×2^4 m^(4×3) n^(-2×4)

4 (-2) = -8:

3×2^4 m^(4×3) n^(-8)

4×3 = 12:

(3×2^4 m^12)/(n^8)

2^4 = (2^2)^2:

(3 (2^2)^2 m^12)/(n^8)

2^2 = 4:

(3×4^2 m^12)/(n^8)

4^2 = 16:

(3×16 m^12)/(n^8)

3×16 = 48:

Answer: (48 m^12)/n^8

5 0
3 years ago
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