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jonny [76]
3 years ago
13

Hi!! I need some help with those exercises can anybody help me please !! Thanks you

Mathematics
1 answer:
elena55 [62]3 years ago
6 0

Answer:

Step-by-step explanation:

(a+b)^2=a^(2)+2ab+b^(2)

(a-b)^2=a^(2)-2ab+b^(2)

13)

(x+2)^(2)-(x-1)^2

x^(2)+4x+4-(x^(2)-2x+1)

x^(2)+4x+4-x^(2)+2x-1

6x+3

15)

(x+5)^(2)-(x+1)^2

x^(2)+10x+25-(x^(2)+2x+1)

x^(2)+10x+25-x^(2)-2x-1

8x+24

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Use integration by parts to find the integrals in Exercise.<br> ∫(x+6)ex dx.
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Answer:

xe^x+5e^x

Step-by-step explanation:

We have given integral \int (x+6)e^xdx

\int (xe^x+6e^x)dx

\int (I_1+I_2)dx , here I_1=xe^x and I_2=6e^x

Now first integrate I_1

So I_1=\int xe^x

Integrating by part

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I_1=x e^x- e^x

I_2=6\int e^x=6e^x

So I=I_1+I_2=xe^x-e^x+6e^x=xe^x+5e^x

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