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jonny [76]
3 years ago
13

Hi!! I need some help with those exercises can anybody help me please !! Thanks you

Mathematics
1 answer:
elena55 [62]3 years ago
6 0

Answer:

Step-by-step explanation:

(a+b)^2=a^(2)+2ab+b^(2)

(a-b)^2=a^(2)-2ab+b^(2)

13)

(x+2)^(2)-(x-1)^2

x^(2)+4x+4-(x^(2)-2x+1)

x^(2)+4x+4-x^(2)+2x-1

6x+3

15)

(x+5)^(2)-(x+1)^2

x^(2)+10x+25-(x^(2)+2x+1)

x^(2)+10x+25-x^(2)-2x-1

8x+24

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16(4 1/4) distrubuted
ss7ja [257]

Answer:

68

Step-by-step explanation:

Step 1: Convert fraction to improper

4 1/4 = 16/4 + 1/4 = 17/4

Step 2: Multiply 16 and 17/4

16(17/4) = 272/4 = 68

8 0
4 years ago
Decide whether x=2 is a solution of x square+4x-12=0
hjlf

Answer:Yes, it is


Step-by-step explanation:

2^2+4(2)-12=0

4+8-12=0

12-12=0

0=0

7 0
3 years ago
On May 14, 1898, a severe hailstorm hit Kansas City. The largest hailstones were 9.5 inches in circumference. Find the radius of
tigry1 [53]
C = \pir
9.5 = 2\pir
\pir = 4.75
r = 1.511971959 
The number above should be rounded to the nearest 2 decimal places, so the answer is 1.51.
6 0
3 years ago
In parallelogram WXYZ, ∠W and ∠X are adjacent. The measure of ∠X is three times the measure of ∠W. Which equation gives the exac
Juliette [100K]
The answer is b, because you have to multiply them by 3

5 0
4 years ago
Which graph represents the solution to the inequality x+3 greater than or equal to 2?
Shalnov [3]

Answer:

x+3\ge 2=\begin{bmatrix}\mathrm{Solution:}\:&\:x\ge \:\:-1\:\\ \:\:\mathrm{Interval\:Notation:}&\:[-1,\:\infty \:\:)\end{bmatrix}

Please check the attached graph.

Step-by-step explanation:

We know that 'greater than or equal' is represented as '≥'.

Thus, inequality ''x+3 greater than or equal to 2'' is represented as:

x+3\ge 2

<u><em>Solving inequality</em></u>

x+3\ge 2

subtract 3 from both sides

x+3-3\ge \:2-3

simplify

x\ge \:-1

Thus,

x+3\ge 2=\begin{bmatrix}\mathrm{Solution:}\:&\:x\ge \:\:-1\:\\ \:\:\mathrm{Interval\:Notation:}&\:[-1,\:\infty \:\:)\end{bmatrix}

Please check the attached graph.

3 0
3 years ago
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