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omeli [17]
3 years ago
6

Explain how your battery works. (You may want to look at the Electric Current lesson) What are some possible materials you could

use to make your battery?
Physics
1 answer:
Lisa [10]3 years ago
6 0

Answer:

A battery is made up of three parts. The Cathode (positive end +) , the Anode (negative end -) and the electrolyte. The electrolyte allows electrical charges to travel between the cathode and anode. This chemical reactions creates the flow of electricity supplying the electrical voltage potential to power a circuit.

Typical materials of a battery are as follows

- Anode most often is made of zinc

- Manganese dioxide acting as Cathode.

- the electrolyte between and inside contains ions

Explanation:

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In order for an object to speed up, ---- must be in the same direction.
lutik1710 [3]

Answer:

2.....................

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3 years ago
What is a medum and why do waves travel through them?
bearhunter [10]
A medium is a substance or material that carries the wave. Sounds waves need a medium in order to travel through a wave to help it travel as it cannot travel through a vacuum. Mechanical waves need a medium to transport energy.
6 0
3 years ago
An elevator lifts a total mass of 1800 kg, a distance of 60 m in 60 s. How much power does the elevator generate?
emmainna [20.7K]

Answer:

17640

Explanation:

Power = workdone/time

Power = (force x displacement)/time

Power = (mg x 60)/60

Power = (1800 x 9.8 x 60)/60

=> power = 17640 watt

3 0
3 years ago
No living things with the movement characteristics
vazorg [7]

Is there a question in here somewhere?

8 0
3 years ago
A horizontal circular platform (m = 119.1 kg, r = 3.23m) rotates about a frictionless vertical axle. A student (m = 54.3kg) walk
Murrr4er [49]

Answer:

\omega_2=5.1rad/s

Explanation:

Since there is no friction angular momentum is conserved. The formula for angular momentum thet will be useful in this case is L=I\omega. If we call 1 the situation when the student is at the rim and 2 the situation when the student is at r_2=1.39m from the center, then we have:

L_1=L_2

Or:

I_1\omega_1=I_2\omega_2

And we want to calculate:

\omega_2=\frac{I_1\omega_1}{I_2}

The total moment of inertia will be the sum of the moment of intertia of the disk of mass m_D=119.1 kg and radius r_D=3.23m, which is I_D=\frac{m_Dr_D^2}{2}, and the moment of intertia of the student of mass m_S=54.3kg at position r (which will be r_1=r=3.23m or r_2=1.39m) will be I_{S}=m_Sr_S^2, so we will have:

\omega_2=\frac{(I_D+I_{S1})\omega_1}{(I_D+I_{S2})}

or:

\omega_2=\frac{(\frac{m_Dr_D^2}{2}+m_Sr_{S1}^2)\omega_1}{(\frac{m_Dr_D^2}{2}+m_Sr_{S2}^2)}

which for our values is:

\omega_2=\frac{(\frac{(119.1kg)(3.23m)^2}{2}+(54.3kg)(3.23m)^2)(3.1rad/s)}{(\frac{(119.1kg)(3.23m)^2}{2}+(54.3kg)(1.39m)^2)}=5.1rad/s

6 0
3 years ago
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