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scoundrel [369]
3 years ago
7

a stone is dropped from rest at an initial height h above the surface of the earth. Show that the speed with which it strikes th

e ground is v
Physics
1 answer:
Ksju [112]3 years ago
5 0

Answer:

v=\sqrt{2gh}

Explanation:

We could use conversation of energy. Total distance the stone will cover will be

h=\frac{1}{2} g t^{2}

the Final velocity will be

v=gt\\v=g\sqrt{\frac{2h}{g} }\\ v=\sqrt{2gh}

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A particle with an initial linear momentum of 2.00 kg-m/s directed along the positive x-axis collides with a second particle, wh
ladessa [460]

Answer:

a) p₂ = 1.88 kg*m/s

   θ = 273.4 º

b)  Kf = 37% of Ko

Explanation:

a)

  • Assuming no external forces acting during the collision, total momentum must be conserved.
  • Since momentum is a vector, their components (projected along two axes perpendicular each other, x- and y- in this case) must be conserved too.
  • The initial momenta of both particles are directed one along the x-axis, and the other one along the y-axis.
  • So for the particle moving along the positive x-axis, we can write the following equations for its initial momentum:

       p_{o1x} = 2.00 kg*m/s (1)

       p_{o1y} = 0 (2)

  • We can do the same for the particle moving along the positive y-axis:

        p_{o2x} = 0 (3)

        p_{o2y} = 4.00 kg*m/s (4)

  • Now, we know the value of magnitude of the final momentum p1, and the angle that makes with the positive x-axis.
  • Applying the definition of cosine and sine of an angle, we can find the x- and y- components of the final momentum of the first particle, as follows:

       p_{f1x} = 3.00 kg*m/s * cos 45 = 2.12 kg*m/s (5)

      p_{f1y} = 3.00 kg*m/s sin 45 = 2.12 kg*m/s  (6)

  • Now, the total initial momentum, along these directions, must be equal to the total final momentum.
  • We can write the equation for the x- axis as follows:

       p_{o1x} + p_{o2x} = p_{f1x} + p_{f2x}  (7)

  • We know from (3) that p₀₂ₓ = 0, and we have the values of p₀1ₓ from (1) and pf₁ₓ from (5) so we can solve (7) for pf₂ₓ, as follows:

       p_{f2x} = p_{o1x} - p_{f1x} = 2.00kg*m*/s - 2.12 kg*m/s = -0.12 kg*m/s (8)

  • Now, we can repeat exactly the same process for the y- axis, as follows:

       p_{o1y} + p_{o2y} = p_{f1y} + p_{f2y}  (9)

  • We know from (2) that p₀1y = 0, and we have the values of p₀₂y from (4) and pf₁y from (6) so we can solve (9) for pf₂y, as follows:

       p_{f2y} = p_{o1y} - p_{f1y} = 4.00kg*m*/s - 2.12 kg*m/s = 1.88 kg*m/s (10)

  • Since we have the x- and y- components of the final momentum of  the second particle, we can find its magnitude applying the Pythagorean Theorem, as follows:

       p_{f2} = \sqrt{p_{f2x} ^{2} + p_{f2y} ^{2} }  = \sqrt{(-0.12m/s)^{2} +(1.88m/s)^{2}} = 1.88 kg*m/s (11)

  • We can find the angle that this vector makes with the positive x- axis, applying the definition of tangent of an angle, as follows:

       tg \theta = \frac{p_{2fy} }{p_{2fx} } = \frac{1.88m/s}{(-0.12m/s} = -15.7 (12)

  • The angle that we are looking for is just the arc tg of (12) which measured in a counter-clockwise direction from the positive x- axis, is just 273.4º.

b)

  • Assuming that both masses are equal each other, we find that the momenta are proportional to the speeds, so we find that the relationship from the final kinetic energy and the initial one can be expressed as follows:

       \frac{K_{f}}{K_{o} } = \frac{v_{f1}^{2} + v_{f2} ^{2}}{v_{o1}^{2} + v_{o2} ^{2} } = \frac{12.5}{20} = 0.63 (13)

  • So, the final kinetic energy has lost a 37% of the initial one.

6 0
2 years ago
5. which event marks the end of both the Paleozoic era and the mesozoic era?
olganol [36]
The answer is A. Cenozoic
6 0
3 years ago
Read 2 more answers
The talk test can be used to measure the
Alla [95]

The talk test can be used to measure the <u>intensity of an activity</u>

<u>Option: B</u>

<u>Explanation:</u>

The talk test is usually used to measure the intensity of a particular activity when a person talks during that activity. This is mostly used in cardiovascular patients to measure the intensity of the exercise.

For example, when a person can talk during exercising, it means that he is able to use the oxygen to create energy for the muscles. i.e he will be in aerobic state. Incase, he is not able to talk any more during his exercise, it means that the breathing rate has reached a particular ventilatory  threshold.

So now the body is creating energy from the stored system such as muscle glucose and creatine. Thus this talk test helps to determine in which way your body creates energy, aerobic or non aerobic.

5 0
3 years ago
In Motion studies, the position in space and time at which motion began is selected as the ______.
Sonbull [250]
I am pretty sure that the answer is B.
6 0
3 years ago
Read 2 more answers
A farmer lifts his hay bales into the top loft of his barn by walking his horse forward with a constant velocity of 8 ft/s. Dete
g100num [7]

Answer:

Velocity = 8 ft/s

Acceleration = 0 m/s²

Explanation:

Since, the horse is moving with a constant velocity, whose magnitude is given as equal to 8 ft/s. Therefore, it will have the same velocity when it is 10 ft away from the barn. And the velocity of hay bale will be same as the velocity of horse, as the horse is carrying the bales. Therefore:

<u>Velocity = 8 ft/s</u>

Coming to the second part of the question, which relates to the acceleration of the hay bale, when horse is 10 ft away from the barn. The formula for acceleration is given as:

Acceleration = Change in Velocity/ Time

But, the velocity of the horse in constant, which means there is no change in velocity. Hence,

Change in Velocity = 0

Therefore,

Acceleration = 0/Time

<u>Acceleration 0 m/s²</u>

6 0
3 years ago
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