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MatroZZZ [7]
3 years ago
9

Jupiter has a mass about 300x that of Earth, and its radius is about 11x that of Earth. What would be the approximate weight of

a 1 kg rock on the surface of Jupiter?
Physics
1 answer:
erica [24]3 years ago
4 0

Answer:

W = 24.01 N

Explanation:

given,

mass of Jupiter = 300 x

radius = 11 x

weight of 1 Kg on Jupiter = ?

using equation of acceleration of gravity

 g =\dfrac{GM}{r^2}

mass of Jupiter = 300 M

radius of the Jupiter = 11 R

now, acceleration due to gravity

 g' =\dfrac{G(300M)}{(11R)^2}

 g' =\dfrac{300}{121}\dfrac{GM}{R^2}

 g' =2.45 g

acceleration due to gravity of Jupiter

 g' = 24.01 m/s²

Weight of the rock  in Jupiter

W = m g'

W = 1 x 24.01

W = 24.01 N

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Answer:

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Explanation:

from the question we have :

speed = 1 rps = 1x 60 = 60 rpm

coefficient of friction (μ) = 0.1

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to get how far from the center of the disk the coin can be placed without having to slip off we equate the formula for the centrifugal force with the frictional force on the turntable force

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where

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now

velocity = 6.28 x r = 6.28 r

now substituting the value of velocity into equation 1

v^2 / r =  g x μ

(6.28r)^2 / r = 9.8 x 0.1

39.5 x r = 0.98

r = 0.02 m

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