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MatroZZZ [7]
3 years ago
9

Jupiter has a mass about 300x that of Earth, and its radius is about 11x that of Earth. What would be the approximate weight of

a 1 kg rock on the surface of Jupiter?
Physics
1 answer:
erica [24]3 years ago
4 0

Answer:

W = 24.01 N

Explanation:

given,

mass of Jupiter = 300 x

radius = 11 x

weight of 1 Kg on Jupiter = ?

using equation of acceleration of gravity

 g =\dfrac{GM}{r^2}

mass of Jupiter = 300 M

radius of the Jupiter = 11 R

now, acceleration due to gravity

 g' =\dfrac{G(300M)}{(11R)^2}

 g' =\dfrac{300}{121}\dfrac{GM}{R^2}

 g' =2.45 g

acceleration due to gravity of Jupiter

 g' = 24.01 m/s²

Weight of the rock  in Jupiter

W = m g'

W = 1 x 24.01

W = 24.01 N

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A 4.0-kg object has 72 J of kinetic energy.<br> Determine its speed.
Svetlanka [38]

Answer:

6m/s

Explanation:

v = sqrt of 2KE/m

Where:

KE = kinetic energy

m = mass of a body

v = velocity of a body

= sqrt of 2(72)/4

= sqrt of 144/4

= sqrt of 36

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8 0
2 years ago
An elevator motor provides 45.0 kW of power while lifting an elevator 35.0 m. If the elevator contains seven passengers each wit
mylen [45]

Find how much work ∆<em>W</em> is done by the motor in lifting the elevator:

<em>P</em> = ∆<em>W</em> / ∆<em>t</em>

where

• <em>P</em> = 45.0 kW = power provided by the motor

• ∆<em>W</em> = work done

• ∆<em>t</em> = 20.0 s = duration of time

Solve for ∆<em>W</em> :

∆<em>W</em> = <em>P</em> ∆<em>t</em> = (45.0 kW) (20.0 s) = 900 kJ

In other words, it requires 900 kJ of energy to lift the elevator and its passengers. The combined mass of the system is <em>M</em> = (<em>m</em> + 490.0) kg, where <em>m</em> is the mass of the elevator alone. Then

∆<em>W</em> = <em>M</em> <em>g h</em>

where

• <em>g</em> = 9.80 m/s² = acceleration due to gravity

• <em>h</em> = 35.0 m = distance covered by the elevator

Solve for <em>M</em>, then for <em>m</em> :

<em>M</em> = ∆<em>W</em> / (<em>g h</em>) = (900 kJ) / ((9.80 m/s²) (35.0 m)) ≈ 2623.91 kg

<em>m</em> = <em>M</em> - 490.0 kg ≈ 2133.91 kg ≈ 2130 kg

4 0
3 years ago
A car of mass m, traveling at constant speed, rides over the top of a round hill. How do the normal force of the road on the car
dybincka [34]

Answer:

The normal force will be lower than the gravitational force acting on the car. Therefore the answer is N < mg, which is <em>option B</em>.

Explanation:

Over a round hill, the centripetal force acting toward the the radius of the hill supports the gravitational force (mg) of the car. This notion can be expressed mathematically as follows:

At the top of a round hill

Normal force = Gravitational force - centripetal force

At the foot of a round hill

Normal Force = centripetal force + Gravitational force

4 0
3 years ago
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Fittoniya [83]
I don't like the wording of any of the choices on the list.

SONAR generates a short pulse of sound, like a 'peep' or a 'ping',
focused in one direction.  If there's a solid object in that direction,
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source.  The source listens to hear if any of the sound that it sent
out returns to it.  If it hears its own 'ping' come back, it measures
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RADAR works exactly the same way, except RADAR uses radio waves. 


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3 years ago
Is this statement true or false?
Y_Kistochka [10]
The statement is true! 
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Read 2 more answers
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