Two very narrow slits are spaced 1.80 mm apart and are placed 35.0 cm from a screen. What is the distance between the first and
1 answer:
The distance between the first and second dark lines of the interference pattern is mathematically given as
d= 0.107 m
<h3>What is the distance between the first and second dark lines of the interference pattern?</h3>Question Parameters:
Two very narrow slits are spaced 1.80 mm apart and are placed 35.0 cm from a screen
coherent light with 550 nm
Generally, the equation for the distance between the first and second dark lines is mathematically given as
Therefore
d= 550*10^-9*0.35/(1.8*10^-6)
d= 0.107 m
In conclusion, the distance between the first and second dark lines
d= 0.107 m
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Answer:
The magnitude of the acceleration of a proton at a distance of 1.5cm from the bead is 5.6 x10^13m/s².
The magnitude of the acceleration of a proton at a distance of 1.5cm from the bead is 9.8 x10^16m/s².
Explanation:
Newton's second law states that the total sum of the force acting on a particle in motion is equal to the mass of the particle times the acceleration due to the force. So the electric force between the bead and proton is equal to ma. That is,
Fe = kq1*q2/r² = m*a
The proton had a charge of +1.6x10^-19C and a mass of 1.67×10^-27kg
By substituting these values into the equivalent for a we have that the acceleration of the proton at a distance of 1.5cm form the bead is 5.6×10^13m/s²
The proton had a charge of -1.6x10^-19C and a mass of 9.10×10^-31kg
By substituting these values into the equivalent for a we have that the acceleration of the proton at a distance of 1.5cm form the bead is 9.8×10^16m/s²
