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Helen [10]
2 years ago
15

Two very narrow slits are spaced 1.80 mm apart and are placed 35.0 cm from a screen. What is the distance between the first and

second dark lines of the interference pattern when the slits are illuminated with coherent light with l
Physics
1 answer:
Ilya [14]2 years ago
5 0

The distance between the first and second dark lines of the interference pattern is mathematically given as

d= 0.107 m

<h3>What is the distance between the first and second dark lines of the interference pattern?</h3>

Question Parameters:

Two very narrow slits are spaced 1.80 mm apart and are placed 35.0 cm from a screen

coherent light with 550 nm

Generally, the equation for the distance between the first and second dark lines  is mathematically given as

d= \lamda*R/d

Therefore

d= 550*10^-9*0.35/(1.8*10^-6)

d= 0.107 m

In conclusion, the distance between the first and second dark lines

d= 0.107 m

Read more about Distance

brainly.com/question/4931057

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If the magnitude of a positive charge is tripled, what is the ratio of the original value of the electric field at a point to th
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Answer:

b)1 :3

Explanation:

Lets that

The value of a positive charge = q

As we know that electric filed on a point charge given as

E=\dfrac{Kq}{r^2}

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If the value of the charge gets tripled ,q'= 3 q

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E'=\dfrac{Kq'}{r^2}

E'=\dfrac{3Kq}{r^2}

E' = 3 E

Therefore we can say that

\dfrac{E}{E'}==\dfrac{1}{3}

therefore the answer will be --

b)1 :3

3 0
2 years ago
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kakasveta [241]
105 miles because you have to use the gif arable
7 0
2 years ago
Riding in a car, you suddenly put on the brakes. As you experience it inside the car, do Newton's law apply? Do they apply as se
alisha [4.7K]

Answer with Explanation:

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For the person as he presses the brakes his frame is a decelerating frame of reference hence he cannot apply the newtons laws of motion as they are in their original form but if he analyses the motion he has to apply a correction known as  pseudo-force on the object he is analyzing. Pseudo Force has no basis in newton's laws but are a correction that needs to be applied if he wishes to analyse the motion from non inertial frame of reference

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3 0
3 years ago
When tightening a bolt, you push perpendicularly on a wrench with a force of 165 N at a distance of 0.140 m from the center of t
choli [55]

Answer:

Part a)

\tau = 23.1 Nm

Part b)

\tau = 17.05 Foot pound force

Explanation:

As we know that torque is defined as the product of force and its perpendicular distance from reference point

so here we have

\tau = \vec r \times \vec F

now we have

\tau = (0.140)(165)

\tau = 23.1 Nm

Part b)

Now we know the conversion as

1 meter = 3.28 foot

1 N = 0.225 Lb force

now we have

\tau = 23.1 Nm

\tau = 23.1 (0.225 Lb)(3.28 foot)

\tau = 17.05 Foot pound force

3 0
3 years ago
a car whose mass is 1000kg is traveling at a constant speed of 10m/s. Neglecting any friction how much force will the engine hav
AURORKA [14]
This next statement is a big deal.  It should be up on a board, surrounded
by flashing red and yellow lights, and hung on the wall of every Science
classroom.   Although we never see it in our daily lives, it's fundamental to
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<em>Without friction, it doesn't take <u>ANY</u> force to keep a moving object
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<em>Force is only required to <u>change</u> the object's speed, or to
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<em>in which it's moving.</em>

The answer to the question is:  On a level road, and neglecting any friction,
the engine doesn't have to supply ANY force to keep the car going at the
same speed.
7 0
3 years ago
Read 2 more answers
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