Two very narrow slits are spaced 1.80 mm apart and are placed 35.0 cm from a screen. What is the distance between the first and
1 answer:
The distance between the first and second dark lines of the interference pattern is mathematically given as
d= 0.107 m
<h3>What is the distance between the first and second dark lines of the interference pattern?</h3>Question Parameters:
Two very narrow slits are spaced 1.80 mm apart and are placed 35.0 cm from a screen
coherent light with 550 nm
Generally, the equation for the distance between the first and second dark lines is mathematically given as
Therefore
d= 550*10^-9*0.35/(1.8*10^-6)
d= 0.107 m
In conclusion, the distance between the first and second dark lines
d= 0.107 m
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Answer:
Minimum thickness will be 100 nm
Explanation:
We have given refractive index is n = 1.5
Wavelength of the light incidence = 600 nm
We have to find the smallest thickness of the film so that there will be minimum light reflect
For minimum thickness of non reflecting film
, here t is thickness,
is wavelength and n is refractive index
Putting all values
So minimum thickness will be 100 nm