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Annette [7]
3 years ago
5

A small glass bead has been charged to 8.0 nc. what is the magnitude of the electric field 2.0 cm from the center of the bead?

Physics
1 answer:
astraxan [27]3 years ago
7 0
<span>Charge of the glass bead Q = 8.0 x 10^-9 C Distance d = 2.0 cm = 0.02 m Coulombs constant K = 8.99 x 10^9 Nm^2/C^2 Electric Field E = k x Q / d^2 = 8.99 x 10^9 x 8.0 x 10^-9 / (0.02)^2 E = 71.92 / 0.0004 = 17.98 x 10^4 The electric field is 1.8 x 10^5 N/C</span>
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Diano4ka-milaya [45]
The question in choice-C is the correct answer to your question.

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You are making a telephone out of two aluminum cans and some string. You can choose between two types of string: a 2-m length of
Nataliya [291]

Answer:

C)You should use the thin cooking twine.

Explanation:

A)You can choose either because they are the same length and will produce the same wave speed.

B)You should use the heavy rope.

C)You should use the thin cooking twine.

The speed of wave in a string is given by the following formula:

|v| = \sqrt{\frac{F_T}{u} }

Where |v| = speed of wave, F_T = tension in the string, and μ = mass per length of the string.

<em>Even though the two strings have the same length, the μ (mass/length) for the heavy rope will be more than the that of a thin rope. Consequently, the </em>F_T<em>:μ for the thin rope will be higher than that of the heavy rope and as such, gives a bigger |</em>v<em>|. </em>

Therefore, the thin rope should be used in order to get a faster wave speed in the telephone.

The correct option is C.

3 0
3 years ago
An atom is.......Help?
Dmitry_Shevchenko [17]
The smallest level of ordination in living things. Every living thing is made up of atoms. Atoms are made up of protons, neutrons, and electrons.
5 0
3 years ago
( 8c5p79) A certain force gives mass m1 an acceleration of 13.5 m/s2 and mass m2 an acceleration of 3.5 m/s2. What acceleration
Talja [164]

Answer:

4.725 m/s^{2}

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Also making mass the subject of the formula m=\frac {F}{a}

For m1= \frac {F}{13.5} and m2=\frac {F}{3.5} hence F=(m2-m1)a= (\frac {F}{3.5}-\frac {F}{13.5})a=0.2116402116\\\frac {1}{a}=0.2116402116\\a=4.725 m/s^{2}

4 0
3 years ago
A car is traveling at a 20.0 m/s for 7.00 s and then suddenly comes to a stop over a 3 s period.
Delicious77 [7]

Answer: A) Deceleration of the car is -6.6667 m/s² while it came to stop.

B) The total distance the car travels is 200 meter during the 10 s period.

Explanation:

Given Data

Initial velocity of the car ($$v_{i}$$) =   20.0 m/s

Final velocity of the car (v_{f}) = 0 m/s

Time (in motion) =7.00 s

Time (in rest) =3 s

To find - A) car's deceleration while it came to a stop

              B) the total distance the car travels in 10 s

A) The formula to find the deceleration is

Deceleration = (( final velocity - initial velocity ) ÷ Time)        (m/s²)

Deceleration = ((v_{f}) - ($$v_{i}$$)) ÷ time     (m/s²)

Deceleration =  ( 0.0 - 20 ) ÷ 3      (m/s²)

Deceleration =   (- 20) ÷ 3  (m/s²)

Deceleration   =  - 6.6667 m/s²

(NOTE : Deceleration is the opposite of acceleration so the final result must have the negative sign)

The car's deceleration is  - 6.6667 m/s² while it came to a stop

B) The formula to find the distance traveled by the car is  

Distance traveled by the car is equals to the product of the speed and time

Distance = Speed × Time  (meter)

Distance = 20.0 × 10

Distance = 200 meters

The total distance the car travels during the period of 10 s is 200 meters

7 0
3 years ago
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