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3 years ago

HELP PLEASE!! WILL MARK BRAINLIEST!!!!

Mathematics

1 answer:

elixir [45]3 years ago

4 0

Answer:

see below

Step-by-step explanation:

$\frac{1}{x^{2} } + \frac{2}{y}/ \frac{5}{x} -\frac{6}{y^2}$

find common denominator and add the fractions in numerator and denominator:

1/x² + 2/y = y+2x²/x²y

5/x -6/y² =5y² -6x/xy²

(y+2x²)/x²y / (5y²-6x)/xy² change into multiplication

(y+2x²)/x²y * xy²/(5y²-6x)

$\frac{y+2x^{2} }{x^{2} y} *\frac{xy^{2} }{5y^{2}-6x }$ simplify

y(y+2x²)/ x(5y²-6x)

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ANSWER

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3 years ago

A poster is to have an area of 210 in2 with 1 inch margins at the bottom and sides and a 2 inch margin at the top. find the exac

slavikrds [6]

Let

x-------> the length side of the poster

y-------> the width side of the poster

we know that

Area of the poster is equal to

$210=x*y\\\\ y=\frac{210}{x}$ -------> equation $1$

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$Aprinted=(x-2)*(y-3)\\ Aprinted=xy-3x-2y+6$ ----> equation $2$

substitute equation $1$ in equation $2$

$Aprinted=[210]-3x-2*[\frac{210}{x}]+6$

using a graph tool

Find the vertex of the graph

The vertex of the graph is the point that represent the value of x for the largest printed area

see the attached figure

the vertex is the point $(11.83,145)$

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$x=11.83 in$

find the value of y

$y=\frac{210}{x} \\ \\ y=\frac{210}{11.83} \\ \\ y=17.75in$

therefore

the answer is

The dimensions of the poster are $11.83 in x 17.75 in$

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andrey2020 [161]

Answer:

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