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anyanavicka [17]
3 years ago
9

HELP PLEASE!! WILL MARK BRAINLIEST!!!!

Mathematics
1 answer:
elixir [45]3 years ago
4 0

Answer:

see below

Step-by-step explanation:

\frac{1}{x^{2} } +  \frac{2}{y}/ \frac{5}{x} -\frac{6}{y^2}

find common denominator and add the fractions in numerator and denominator:

1/x² + 2/y = y+2x²/x²y

5/x -6/y² =5y² -6x/xy²

(y+2x²)/x²y / (5y²-6x)/xy² change into multiplication

(y+2x²)/x²y * xy²/(5y²-6x)

\frac{y+2x^{2} }{x^{2} y} *\frac{xy^{2} }{5y^{2}-6x } simplify

y(y+2x²)/ x(5y²-6x)

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Find the measure of ∠BAC. Create another angle with the same measure. Measure the new angle to verify that it has the same angle
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Answer:

The position and orientation of the new angle may vary, but it should have the same angle measure as ∠BAC

.Step-by-step explanation:

4 0
2 years ago
Show me how to solve step by step please
andrew-mc [135]

Answer:

188

Step-by-step explanation:

88 + 6= 94

94 + 94 = 188

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Answer:

A. ?

B. ?

C. ?

1. Different

2. Same

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Step-by-step explanation:

I kinda went off what I knew

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4 0
3 years ago
Read 2 more answers
What is the vertex of (x) = –16x² + 64x + 80.
cricket20 [7]

Answer:

<h3>            (2, 124)</h3>

Step-by-step explanation:

f(x) = a(x - h)² + k      - the  vertex form of the equation of the parabola with vertex (h, k)

f(x) = -16x^2+ 64x + 80\\\\f(x) = -16(x^2- 4x) + 80\\\\f(x) = -16(\underline {x^2-2\cdot2x\cdot2+2^2}-2^2) + 80\\\\f(x) = -16\big[(x-2)^2-4\big] + 80\\\\f(x) = -16(x-2)^2+64 + 80\\\\\bold{f(x)=-16(x-2)^2+124\quad\implies\quad h=2\,,\quad k=124}

<u>The vertex is </u><u>(2, 124)</u>

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