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3 years ago

Anybody know ??????

Mathematics

1 answer:

natka813 [3]3 years ago

6 0

Answer:

The answer is-8 (A.)

Step-by-step explanation:

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Simplify 4^9/4^3 A)4^5 B)4^6 C)4^12 D)4^27

atroni [7]

$\frac{4^9}{4^3}=4^{9-3}=4^6$

B)4^6

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3 years ago

Which means the sum of w and 3.4 is greater than or equal to 10.5?

DochEvi [55]

Sounds that you have several answer choices. If that's the case, you need to share those choices. All of them are probably inequalities.

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3 years ago

Write –1.2 as a mixed number.

Luden [163]

Answer:

-1 1/5

Step-by-step explanation: cause calculator

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Mrs. CADY CONSTRUCTS A CUBE WITH 512 MAGNETIC BLOCKS. STUDENTS IN HER TWO CLASSES WILL EACH MAKE AN IDENTICAL CUBE. THERE ARE 28

Lilit [14]

YOU DON"T HAVE TO YELL

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3 years ago

A survey of 1,562 randomly selected adults showed that 522 of them have heard of a new electronic reader. The accompanying techn

tester [92]

Answer:

a) We want to test the claim that 35% of adults have heard of the new electronic reader, then the system of hypothesis are.:

Null hypothesis: $p=0.35$

Alternative hypothesis: $p \neq 0.35$

And is a two tailed test

b) $z=\frac{0.334 -0.35}{\sqrt{\frac{0.35(1-0.35)}{1562}}}=-1.326$

c) $p_v =2*P(z$

d) Null hypothesis: $p=0.35$

e) Fail to reject the null hypothesis because the P-value is greater than the significance level, alpha.

Step-by-step explanation:

Information provided

n=1562 represent the random sample selected

X=522 represent the people who have heard of a new electronic reader

$\hat p=\frac{522}{1562}=0.334$ estimated proportion of people who have heard of a new electronic reader

$p_o=0.35$ is the value to verify

$\alpha=0.05$ represent the significance level

z would represent the statistic

$p_v$ represent the p value

Part a

We want to test the claim that 35% of adults have heard of the new electronic reader, then the system of hypothesis are.:

Null hypothesis: $p=0.35$

Alternative hypothesis: $p \neq 0.35$

And is a two tailed test

Part b

The statistic for this case is given :

$z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}}$ (1)

Replacing the info given we got:

$z=\frac{0.334 -0.35}{\sqrt{\frac{0.35(1-0.35)}{1562}}}=-1.326$

Part c

We can calculate the p value using the laternative hypothesis with the following probability:

$p_v =2*P(z$

Part d

The null hypothesis for this case would be:

Null hypothesis: $p=0.35$

Part e

The best conclusion for this case would be:

Fail to reject the null hypothesis because the P-value is greater than the significance level, alpha.

5 0

3 years ago