1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Art [367]
3 years ago
13

The cross-sectional areas of a triangular prism and a right cylinder are congruent. The triangular prism has a height of 5 units

, and the right cylinder has a height of 5 units. Which conclusion can be made from the given information?
The volume of the prism is half the volume of the cylinder.
The volume of the prism is twice the volume of the cylinder.
The volume of the prism is equal to the volume of the cylinder.
The volume of the prism is not equal to the volume of the cylinder.
Mathematics
1 answer:
zalisa [80]3 years ago
5 0

Answer:

C. The volume of the prism is equal to the volume of the cylinder

Step-by-step explanation:

Given

Congruent area of cylinder and triangular prism

Height of triangular prism = 5 units

Height of Cylinder = 5 units

Required

Relationship between the volumes of both shapes.

Let H₁ and H₂ represent the height of the cylinder and the triangular prism

H₁ = H₂ = 5 units

From the question, we have that both shapes have a congruent area.

This means that they have the same base area.

Let this be represented by A

So;

Calculating the volume of the cylinder

V₁ = Base Area (A) * Height (H₁)

V₁ = A * 5

V₁ = 5A

Calculating the volume of the triangular prism

V₂ = Base Area (A) * Height (H₂)

V₂ = A * 5

V₂ = 5A

Comparing both volumes.

V₁ = 5A

V₂ = 5A

Since V₁ = V₂ = 5A, then we can conclude that both shapes have the same volume.

You might be interested in
A water sprinkler sends water out in a circular pattern. How large is the watered area if the radius of the watering pattern is2
Mamont248 [21]

Answer:

Step-by-step explanation:

Simply put, it is similar to finding the area of a circle.

Therefore, a=pi*r^2

a=pi*23^2

a=529pi

a=1661.9 ft^2

6 0
2 years ago
Find the perimeter: a polygon with sides 2.1 cm, 2.1 cm, 1 cm, 3.3 cm, and 1 cm
Nostrana [21]

Hello!

P = 2,1cm + 2,1cm + 1cm + 3,3cm + 1cm => P = 4,2cm + 1cm + 3,3cm + 1cm => P = 5,2cm + 3,3cm + 1cm => P = 8,5cm + 1cm => P = 9,5cm

Answer: D. 9,5cm

Good luck! :)

7 0
3 years ago
Read 2 more answers
What is the slope of the line that passes through (-3,2) and (1,2)
TEA [102]
(-3,2)(1,2)...notice that the y values are the same.....when the y values are the same u have a horizontal line with a 0 slope.

IF the x values would have been the same (instead of the y values), then u would have had a vertical line with an undefined slope.
6 0
3 years ago
Read 2 more answers
An icicle has a volume of 3769.91 mm if this icicle Drips at a rate of 75 mm/min How long will it take the icicles completely me
kvasek [131]

Answer:

The answer is 3,019.92 cubic millimeter

Step-by-step explanation:

take 375 plus 375 to get 750

then 3769.91 - 750 to get the 3,019.92

3 0
4 years ago
Read 2 more answers
I need help with 1-2.b
olya-2409 [2.1K]

Answer:

it is a i thick

Step-by-step explanation:

7 0
4 years ago
Other questions:
  • -2w^2+201.02=66.54<br> Round to the nearest hundredth
    10·1 answer
  • What is the circumference of a circle with a radius of 6.1 centimeters?
    5·2 answers
  • Help help !!!!!!!!!!!!!!!!!!!!!!!
    15·1 answer
  • Solve the equation 9 equals negative d + 17
    14·2 answers
  • In which cell structure does MOST of the process of cellular respiration take place?A.nucleusB.vacuoleC.cell wallD.mitochondrion
    6·1 answer
  • How do you do this????
    14·2 answers
  • 5x+2x=12 what is x. Jejejenenenennenxnddn
    6·2 answers
  • I need to find the sum of this equation
    15·1 answer
  • In his boat, Sheldon can travel 45 mi downstream in the same time that it takes to travel 9 mi upstream. If the rate of the curr
    12·1 answer
  • 100 POINTS i need help fast!
    10·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!