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Alex777 [14]
3 years ago
7

In 1985, the cost of clothing for a certain familiy was $620. In 1995, 10 years later, the cost of clothing for this famility wa

s $1000. Assuming the cost increased linearly, what was the cost of this familiy's clothing in 1991
Mathematics
1 answer:
Sholpan [36]3 years ago
6 0

Answer:

$848

Step-by-step explanation:

Calculation for the cost of this familiy's clothing in 1991

First step is to calculate the amount that is increase per year

Increase per year= ($1000-$620)/(1995-1985)

Increase per year= 380/10

Increase per year= $38

Now let y be :38*x + $620 and let x be 6 years (1991-1985)

Second step is to calculate the cost of the clothing in 1991

y = 38*6 + 620

y=228+620

y = $848

Therefore the cost of this familiy's clothing in 1991 will be $848

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Answer:

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Step-by-step explanation:

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2 years ago
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8 times of the eight term of an arithmetic progression is equal to 12 times of the twelfth term. find its first term if the comm
Ilya [14]

Answer:

a₁ = 38

Step-by-step explanation:

Given AP, where:

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=============

<h3>Solution</h3>

aₙ = a₁ + (n-1)d

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8a₈ = 12a₁₂

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6 0
3 years ago
The scatter plot below shows the number of pizzas sold during weeks when different numbers of coupons were issued. The equation
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Answer:

94 pizzas will be sold

Step-by-step explanation:

We have to use the equation and replace 15 with x.

x=15

y=3.4x + 43

y=3.4(15) + 43

y=51 + 43

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There will be 94 pizzas sold nightly if 15 coupons were issued.

6 0
2 years ago
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I need help I would really thank whoever answers this for me
Mars2501 [29]
To do these problems, you plug in the ‘n’ value given into the equation.

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24 - 3
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b. 1/2b + 5 : b = 14
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Please help with this math question thanks!!!
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The surface area is
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