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Alex777 [14]
3 years ago
7

In 1985, the cost of clothing for a certain familiy was $620. In 1995, 10 years later, the cost of clothing for this famility wa

s $1000. Assuming the cost increased linearly, what was the cost of this familiy's clothing in 1991
Mathematics
1 answer:
Sholpan [36]3 years ago
6 0

Answer:

$848

Step-by-step explanation:

Calculation for the cost of this familiy's clothing in 1991

First step is to calculate the amount that is increase per year

Increase per year= ($1000-$620)/(1995-1985)

Increase per year= 380/10

Increase per year= $38

Now let y be :38*x + $620 and let x be 6 years (1991-1985)

Second step is to calculate the cost of the clothing in 1991

y = 38*6 + 620

y=228+620

y = $848

Therefore the cost of this familiy's clothing in 1991 will be $848

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Answer:

h=15,7 ft

l1=19.8

l2=l1=19.8

Step-by-step explanation:

A=(b×h)/2

110=x×14/2

x×14=220

x=220/14=15,7

h=15.7 ft

l=rad(144+246.7)=19,8

l1=l2=19,8

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3 years ago
What are 2 points on the graph for 6x-5y=25
zepelin [54]
To find any two random point on the graph of 6x-5y=25, we can just plug in any two values for x and solve for y, and find the 2 points in the form of (x,y).

So lets plug in x=0.

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\sf 6(0)-5y=25
\sf -5y=25
\sf y=-5
So one point is (0,-5)

And to find another point, we can plug in x=1

\sf 6x-5y=25
\sf 6(1)-5y=25
\sf 6-5y=25
\sf -5y=25-6
\sf -5y=19
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\sf y=-3.8
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8 0
3 years ago
ASAP! GIVING BRAINLIEST! Please read the question THEN answer correctly! No guessing. Show your work or give an explaination.
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Answer:

Answer is (b) The worker with 40 hours of training is paid $1400 per month

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Consider the line given by the equation: 2x - y= -2
Klio2033 [76]

Answer:

Step-by-step explanation:

look at 2=x-y=2

move this term to the left (2)

it becomes 2=x-y+2=0

and thats your results

Examples: x^2-2x=-1, 3x-x-x+a-a=5, (x^2-1)/(x+1), 2x-(x+x)

7 0
3 years ago
A number, x, rounded to 2 significant figures is 1300<br>Write down the error interval for x.​
nikitadnepr [17]

Answer:

[1250,1350).

Step-by-step explanation:

It is given that a number, x, rounded to 2 significant figures is 1300.

It is possible if,

1. The value of x is greater than of equal to 1250 and less than or equal to 1300.

i.e., 1250\leq x\leq 1300     ...(1)

2. The value of x is greater than of equal to 1300 and less than 1350.

i.e., 1300\leq x       ...(2)

On combining (1) and (2), we get

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1350 is not included in the error interval for x.​

Interval notation is [1250,1350).

Therefore, the error interval for x is [1250,1350).

7 0
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