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3 years ago

PLS PLS HELP FAST. Given an isosceles triangle with a leg length of 12. Determine the length of the hypotenuse.

Mathematics

1 answer:

dolphi86 [110]3 years ago

3 0

Answer:

12*sqrt(3)

Step-by-step explanation:

since it is isosceles its angles are 45, 45, 90, therefore the hypotenuse is 12*sqrt(3).

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The equation of a circle is given below. (x-0.5)^{2}+(y-3.5)^{2} = 16(x−0.5) 2 +(y−3.5) 2 =16left parenthesis, x, minus, 0, poin

Mashutka [201]

Answer:

<h2>The radius is 4 units long.</h2>

Step-by-step explanation:

The given equation is

$(x-0.5)^{2} +(y-3.5)^{2} =16$

This equation belongs to a circle, which center is at (0.5, 3.5) and its radius is 4.

You can deduct its elements, becase this equation of the circle is explicit, which means the constant term represents the square power of the radius. Solving that, we have

$r^{2} = 16\\r=\sqrt{16}\\ r=4$

Therefore, the radius is 4 units long.

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2 years ago

I NEEDDD HELPPPP ASAPPPP ITS URGENTTT!!!!

natulia [17]

Answer:

(x-6)^2+(y-14)^2=4

Step-by-step explanation:

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2 years ago

Solve the inequality <br> -7<3x+5 less than or equal to(no sign for that)7

olganol [36]

Answer:

x=-1

Step-by-step explanation:

-7 < 3(x) + 5 ≤ 7

-7 < 3(-1) + 5 ≤ 7

-7 < -3 + 5 ≤ 7

-7 < 2 ≤ 7

6 0

3 years ago

If breadth of a cuboid is one-fourth of its length,height is 5cm and total surface area is 328 cm²,find the length and breadth o

velikii [3]

The length of cuboid is 16 cm and breadth of cuboid is 4 cm.

<h3>How to find the Surface Area of Cuboid?</h3>

A cuboid has 6 rectangular faces. To find the surface area of a cuboid, add the areas of all 6 faces. We can also label the length (L), Breadth (B), and Height (H) of the cuboid and use the formula, SA=2 x ( LB + BH + HL ) , to find the surface area.

Here, We have given that height of the cuboid is 5cm.

Let length of the cuboid = X cm

so, the breadth of the cuboid = $\frac{X}{4}$ cm

also, we have given that total surface area is 328 cm²

Now, put all the values in the formula of Surface Area (SA):

SA = 2 x ( LB + BH + HL )

SA = 2 x ( X²/4 + 5X/4 + 5X )

SA = 2 x ( ( X² + 5X + 20X) / 4 )

SA = ( X² + 5X + 20X ) / 2

X² + 5X + 20X = 328 x 2

X² + 25X = 656

X² + 25X - 656 = 0

using Quadratic Formula: see the attached figure for the formula.

here Discriminant D = b² - 4ac

D = 625 - 4(-656)

D = 3249

on putting value of D or b² - 4ac in the formula we get

X = ( -25 + 57 ) / 2 and ( -25 - 57 ) /2

length can not be negative so we eliminate the second answer.

now, X = 16 cm

breadth = X /4 = 4 cm

Hence, The length of cuboid is 16 cm and breadth of cuboid is 4 cm.

Learn more about " Quadratic Formula " from here: brainly.com/question/2615966

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3 0

1 year ago

A sine function is transformed such that it has a single x-intercept in the interval (0,pi), a period of pi and a y-intercept of

Alex787 [66]

Just to make sure we're using the same language, I'm going to use the function form of:

$y = A\sin(kx) + h$

[] I would agree that k = 2, since the period is only half as long as a normal sine function. So, we so far, have y = A sin(2x) + h. We still need to find A and h.

[] The y-intercept is 3. Remember that the y-intercept happens when x = 0. So, plugging in x = 0 into our formula, we have: 3 = A sin(2*0) + h. In other words, 3 = A sin(0) + h = 0 + h = h. So, we now know that h = 3. The formula is now y = A sin(2x) + 3.

[] Finally, there is a single x-intercept. Picture what the sine function looks like right now, it is floating in the air around y = 3. We need to stretch it vertically until it just grazes the x-axis.

If A = 1, then our sine function bounces between 2 and 4 (+/- 1 around h = 3). But that doesn't touch 0, so no good.

If A = 2, then our sine function bounces between 1 and 5 (+/- 2 around h = 3). Again, not quite touching 0 yet.

The answer should be A = 3, then our sine function bounces between 0 and 6 (+/- 3 around h = 3).

The final formula is y = 3 sin(2x) + 3.

7 0

2 years ago