13.
(a)
for x = 2:
for x = 5
(b)
The graph is:
(c)
Using the graph:
Using the quadratic formula:
![\begin{gathered} x=\frac{-b\pm\sqrt[]{b^2-4ac}}{2a} \\ x=\frac{-21\pm\sqrt[]{21^2-4(-5)(-10)}}{2(-5)} \\ x=\frac{-21\pm\sqrt[]{241}}{-10} \\ x=0.54758 \\ or \\ x=3.6524 \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20x%3D%5Cfrac%7B-b%5Cpm%5Csqrt%5B%5D%7Bb%5E2-4ac%7D%7D%7B2a%7D%20%5C%5C%20x%3D%5Cfrac%7B-21%5Cpm%5Csqrt%5B%5D%7B21%5E2-4%28-5%29%28-10%29%7D%7D%7B2%28-5%29%7D%20%5C%5C%20x%3D%5Cfrac%7B-21%5Cpm%5Csqrt%5B%5D%7B241%7D%7D%7B-10%7D%20%5C%5C%20x%3D0.54758%20%5C%5C%20or%20%5C%5C%20x%3D3.6524%20%5Cend%7Bgathered%7D)
F(x) and g(x) were inverse functions, then if f(a) = b, then g(b) = a
f(x) = (5x+1) / x g(x) = x / (5x+1)
f(1) = 6, but g(6) = 6/31 ≠ 1
So, f(x) and g(x) are NOT inverse functions.
Answer:
m ≥ 0
Step-by-step explanation:
Since the cost is represented by c = 0.12m, the domain should be a positive number, this is because number of minutes can't be written in negative. Therefore, the most reasonable number for the domain would be the set of positive whole numbers which means, m≥0.
Answer:
(3, 2), (6, 4)
Step-by-step explanation:
Since one end (A) of the segment AB is at the origin, the required points will be 1/3 and 2/3 of the coordinates of B:
(1/3)(9, 6) = (3, 2)
(2/3)(9, 6) = (6, 4)
