Answer:
![V_1=8 V_2](https://tex.z-dn.net/?f=V_1%3D8%20V_2)
Explanation:
Given that:
- Area of the plate of capacitor 1= Area of the plate of capacitor 2=A
- separation distance of capacitor 2,
![d_2=d](https://tex.z-dn.net/?f=d_2%3Dd)
- separation distance of capacitor 1,
![d_1=2d](https://tex.z-dn.net/?f=d_1%3D2d)
- quantity of charge on capacitor 2,
![Q_2=Q](https://tex.z-dn.net/?f=Q_2%3DQ)
- quantity of charge on capacitor 1,
![Q_1=4Q](https://tex.z-dn.net/?f=Q_1%3D4Q)
We know that the Capacitance of a parallel plate capacitor is directly proportional to the area and inversely proportional to the distance of separation.
Mathematically given as:
.....................................(1)
where:
k = relative permittivity of the dielectric material between the plates= 1 for air
![\epsilon_0 = 8.85\times 10^{-12}\,F.m^{-1}](https://tex.z-dn.net/?f=%5Cepsilon_0%20%3D%208.85%5Ctimes%2010%5E%7B-12%7D%5C%2CF.m%5E%7B-1%7D)
From eq. (1)
For capacitor 2:
![C_2=\frac{k.\epsilon_0.A}{d}](https://tex.z-dn.net/?f=C_2%3D%5Cfrac%7Bk.%5Cepsilon_0.A%7D%7Bd%7D)
For capacitor 1:
![C_1=\frac{k.\epsilon_0.A}{2d}](https://tex.z-dn.net/?f=C_1%3D%5Cfrac%7Bk.%5Cepsilon_0.A%7D%7B2d%7D)
![C_1=\frac{1}{2} [ \frac{k.\epsilon_0.A}{d}]](https://tex.z-dn.net/?f=C_1%3D%5Cfrac%7B1%7D%7B2%7D%20%5B%20%5Cfrac%7Bk.%5Cepsilon_0.A%7D%7Bd%7D%5D)
We know, potential differences across a capacitor is given by:
..........................................(2)
where, Q = charge on the capacitor plates.
for capacitor 2:
![V_2=\frac{Q}{\frac{k.\epsilon_0.A}{d}}](https://tex.z-dn.net/?f=V_2%3D%5Cfrac%7BQ%7D%7B%5Cfrac%7Bk.%5Cepsilon_0.A%7D%7Bd%7D%7D)
![V_2=\frac{Q.d}{k.\epsilon_0.A}](https://tex.z-dn.net/?f=V_2%3D%5Cfrac%7BQ.d%7D%7Bk.%5Cepsilon_0.A%7D)
& for capacitor 1:
![V_1=\frac{4Q}{\frac{k.\epsilon_0.A}{2d}}](https://tex.z-dn.net/?f=V_1%3D%5Cfrac%7B4Q%7D%7B%5Cfrac%7Bk.%5Cepsilon_0.A%7D%7B2d%7D%7D)
![V_1=\frac{4Q\times 2d}{k.\epsilon_0.A}](https://tex.z-dn.net/?f=V_1%3D%5Cfrac%7B4Q%5Ctimes%202d%7D%7Bk.%5Cepsilon_0.A%7D)
![V_1=8\times [\frac{Q.d}{k.\epsilon_0.A}]](https://tex.z-dn.net/?f=V_1%3D8%5Ctimes%20%5B%5Cfrac%7BQ.d%7D%7Bk.%5Cepsilon_0.A%7D%5D)
![V_1=8 V_2](https://tex.z-dn.net/?f=V_1%3D8%20V_2)
Answer:
Technician B is correct
Explanation:
Freezing is a method of conversion of substance in its liquid state to solid state. It is the process by which a liquid substance changes to a solid at a particular temperature.
Increasing the pressure and decreasing the temperature of a liquid increases its freezing point. For example, in other to freeze water i.e to change water to ice, it has to be kept in a fridge at a temperature lower than the temperature of the water. The essence of covering the fridge after placing the water in the fridge is to increase the pressure of the liquid hence increasing its freezing rate.
Based on the above explanation, it can be concluded that technician B is correct.
K = C + 273, so 27°C = 27+273 = 300 K
1 dg = 100 mg, so 20 dg = 20×100 = 2,000 mg
So it could follow the correct mass for the atom
Can you please stop pasting this question, just go to his profile and ask him.