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Bogdan [553]
2 years ago
13

fill in the blank ,if a charge body touches the disc of an uncharged electroscope the leaves ------------------​

Physics
1 answer:
Ilia_Sergeevich [38]2 years ago
7 0

Answer:

leaves will deverge

Explanation:

because of the nagwtive charge will become positive

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Which of the following does culture contribute to the preferences and<br> behaviors of consumers?
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Values and beliefs

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Aerosol cans use compressed gases to propel the contents out of the can. Which of the following is the best explanation for why
vovangra [49]

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As the can heats, the compressed gases will expand, causing the can to explode

Explanation:

We know that the gases in the aerosol can would assume the shape and volume of the can. The volume of the can would be the volume of the compressed gas.

As heat is added to the can, the aerosol gases would gain kinetic energy and their speed would increase. The gases would begin to expand and would require more space in order to move. This would indirectly increase the pressures between gas molecules and the walls of the can as collisions soars.  

A point would eventually be reached where the gas agitation would lead to an explosion.

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4 years ago
A force of 32.5N stretches a spring of 0.500cm. What force will stretch a similar spring 1.60 cm?​
Vlad [161]

Answer:

104 N

Explanation:

Calculate the spring stiffness:

F = kx

32.5 N = k (0.500 cm)

k = 65 N/cm

Find the force for the new length:

F = kx

F = (65 N/cm) (1.60 cm)

F = 104 N

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3 years ago
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Engine 1 has an efficiency of 0.13 and requires 7200 J of input heat to perform a certain amount of work. Engine 2 has an effici
r-ruslan [8.4K]

Answer:

3,342.86J

Explanation:

<u>Engine 1</u>

Quantity of Input Heat, Q_{H}  = 7200J

Efficiency,  η = 0.13

                           Efficiency,  η =\frac{W}{Q_{H}}

                           ⇒ W = ηQ_{H}

                                W = 0.13 × 7200

                                W = 936J  

<u>Engine 2</u>

Efficiency,  η = 0.28

Since Engine 2 performs same amount of work as Engine 1, then,

                 Work-done by Engine 2 = Work-done by Engine 1

                                       W₂ = W₁ = 936J

                 Efficiency,  η =\frac{W}{Q_{H}}

                 Q_{H} = W / η

                  Q_{H}=\frac{936}{0.28}

                  Q_{H} = 3,342.86J

The input heat require by  the second engine is 3,342.86J

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3 years ago
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