The bridge attached is drawn according to given dimensions, and it doesn't look right. Please double check the given dimensions.
Calculations:
Horizontal part of bottom chord below the 70 degree triangle
= 15.1*cos(70) = 5.16 (which is a major prt of the 6.3 units.
Height of vertical pieces DF and EH
= 15.1*sin(70) = 14.19
Note that structurally, DF and EH do not help in reducing stress on the bridge, since they are perpendicular to the bottom chord.
Therefore
angle B = atan(14.19/(6.3-5.16))=85.41 degrees
I believe the whole geometry does not look right, esthetically, and structurally, since the compression members are much longer than the tension members in the middle. (The vertical members carry no force.)
If you can review the input data, or post a new question, I will be glad to help.
Answer:
Cable attached height (Perpendicular) = 10√3 m
Step-by-step explanation:
Given:
Length of cable (Hypotenuse) = 20 m
Angle θ = 60°
Find:
Cable attached height (Perpendicular)
Computation:
Perpendicular/Hypotenuse = Sinθ
Perpendicular/20 = Sin 60
Perpendicular/20 = √3 / 2
Perpendicular = 10√3
Cable attached height (Perpendicular) = 10√3 m
Answer:
$385
Step-by-step explanation:
Jordan needs $9,240 for her first year of college tuition.
Each of her two grandfathers said they would match what she saves.
Therefore, Jordan and two of her grandfathers share equally the college tuition fee of Jordan.
Therefore, Jordan has to save
dollars .
If Jordan saves this money for a duration of 8 years then in each year she has to save
dollars. (Answer)