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iVinArrow [24]
3 years ago
7

What are plate boundries

Physics
2 answers:
stepan [7]3 years ago
7 0

Answer:

Plate boundaries are the edges where two plates meet. Most geologic activities, including volcanoes, earthquakes, and mountain building, take place at plate boundaries

Plz mark brainliest if this helped :)

Georgia [21]3 years ago
5 0

Answer:

where plates meet

Explanation:

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Calculate the work done (in J) by a 90.0 kg man who pushes a crate 4.25 m up along a ramp that makes an angle of 20.0° with the
Mrrafil [7]

Answer:

W = 3.4x0³ J.

Explanation:

The work done by the man is given by the following equation:

W = F_{t}\cdot d     (1)

<em>where W: is the work, Ft is the total force and d: is the displacement = 4.25 m.</em>  

We need to find first the total force Ft, which is:

Ft = Fm + W

<em>where Fm: is the force exerted by the man = 535 N, W: is the weight = m*g*sin(θ), m: is the mass of the man, g: is the gravitational acceleration = 9.81 m/s², and θ: is the angle = 20.0°.  </em>

F_{t} = Fm + W = 500 N + 90.0 kg*9.81 m/s^{2} * sin(20.0) = 802.0 N

Hence, the work is:

W = 802.0 N \cdot 4.25 m = 3.4 \cdot 10 ^{3} J  

Therefore, the work done by the man is 3.4x10³ J.  

I hope it helps you!      

8 0
3 years ago
What characteristic does a good conductor possess?
zimovet [89]
<span>A good conductor have lots of free electrons present in it As due to very less difference between valence band and conductive band so electrons can be easily available for conducting electricity
HOPE IT HELPS:)</span>
5 0
3 years ago
Read 2 more answers
In addition to stand-alone discussion boards, all of these sites include discussion boards as part of their features except: ​
adell [148]

Answer:

A. Linkedln

Explanation:

In addition to stand-alone discussion boards, all of these sites include discussion boards as part of their features except: ​

A. Linkedln

All other application in addition to stand-alone Google, Yahoo, Microsoft, etc. include discussion board.

8 0
3 years ago
2.
skelet666 [1.2K]
Answer: 290 W
Explanation: I hope this helps you
6 0
3 years ago
Spitting cobras can defend themselves by squeezing muscles around their venom glands to squirt venom at an attacker. Suppose a s
Nezavi [6.7K]

Answer: 1.124 m

Explanation:

This situation is a good example of the projectile motion or parabolic motion, and the main equations that will be helpful in this situations are:  

x-component:  

x=V_{o}cos\theta t   (1)  

Where:  

V_{o}=2.80 m/s is the initial speed  

\theta=39\° is the angle at which the venom was shot

t is the time since the venom is shot until it hits the ground  

y-component:  

y=y_{o}+V_{o}sin\theta t+\frac{gt^{2}}{2}   (2)  

Where:  

y_{o}=0.4 m  is the initial height of the venom

y=0  is the final height of the venom (when it finally hits the ground)  

g=-9.8m/s^{2}  is the acceleration due gravity

Knowing this, let's begin:

First we have to find t from (2):

0=0.4 m+2.8 m/s sin(39\°) t+\frac{-9.8m/s^{2}t^{2}}{2}   (3)

Rearranging (3):  

-4.9 m/s^{2} t^{2} + 1.762 m/s t + 0.4 m=0   (4)  

This is a <u>quadratic equation</u> (also called equation of the second degree) of the form at^{2}+bt+c=0, which can be solved with the following formula:  

t=\frac{-b \pm \sqrt{b^{2}-4ac}}{2a} (5)  

Where:  

a=-4.9  

b=1.762  

c=0.4  

Substituting the known values:  

t=\frac{-1.762 \pm \sqrt{(1.762)^{2} - 4(-4.9)(0.4)}}{2(-4.9)} (6)  

Solving (6) we find the positive result is:  

t=0.517 s (7)

Substituting (7) in (1):

x=2.8 m/s cos(39\°) (0.517 s)   (8)

Finally:

x=1.124 m   (9)

4 0
4 years ago
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