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mestny [16]
3 years ago
15

A book is to be produced with pages of thickness 0.125mm.If the book is to be exactly 1cm thick what is the maximum number of pa

ges it can contain?​
Physics
1 answer:
miskamm [114]3 years ago
5 0

Answer:

1cm=10mm

10cm/0.125mm

80pages

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A skateboarder shoots off a ramp with a velocity of 7.1 m/s, directed at an angle of 61° above the horizontal. The end of the ra
dsp73

Answer:

Highest point reached  = 3.37 m

Explanation:

Initial velocity, = 7.1 m/s

Initial vertical velocity = 7.1 sin 61 = 6.21 m/s

Consider the vertical motion of skateboarder,

We have equation of motion, v² = u² + 2as

          Initial velocity, u = 6.21 m/s

          Acceleration, a = -9.81 m/s²

          Final velocity, v = 0 m/s

         Substituting

                       v² = u² + 2as

                       0² = 6.21² + 2 x -9.81 x s

                       s = 1.97 m

So from ramp the position it goes up by 1.97 m

       Highest point reached = 1.97 + 1.4 = 3.37 m    

6 0
3 years ago
Change in momentum is equal to force times the amount of time the force is applied? True or False?
harina [27]
The answer to this question is false
7 0
3 years ago
A high jumper jumps over a bar that is 2 m above the mat. With what velocity does the jumper strike the mat in the landing area?
docker41 [41]

Answer:

The velocity with which the jumper strike the mat in the landing area is 6.26 m/s.

Explanation:

It is given that,

A high jumper jumps over a bar that is 2 m above the mat, h = 2 m

We need to find the velocity with which the jumper strike the mat in the landing area. It is a case of conservation of energy. let v is the velocity. it is given by :

v=\sqrt{2gh}

g is acceleration due to gravity

v=\sqrt{2\times 9.81\ m/s^2\times 2\ m}

v = 6.26 m/s

So, the velocity with which the jumper strike the mat in the landing area is 6.26 m/s. Hence, this is the required solution.

8 0
3 years ago
Complete the statements about the law of conservation of momentum.
Svetllana [295]

Answer:

complete the statements

Explanation:

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3 years ago
What is the kinetic energy of a 1.00g hailstone falling at 8.50m/s
bearhunter [10]

Answer:

36.125 J

Explanation:

The formula for kinetic energy is KE = .5(m)(v²).

Using the given information, mass = 1 g and v = 8.50.  Plug that information into the equation.  KE = .5(1)(8.50²) = 36.125 J.

4 0
3 years ago
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