Answer:
80m<em>/</em><em>s</em>
Explanation:
Final velocity is given by
v=u+at
when a motorcyclist starts from rest, initial velocity (u) =0
therefore
v=0+4*20
v=80m/s
that's the answer
Explanation:
Given that,
Mass of the rocket, m = 2150 kg
At time t=0 a rocket in outer space fires an engine that exerts an increasing force on it in the +x−direction. The force is given by equation :

Here F = 888.93 N when t = 1.25 s
(c) We can find the value of A first as :

The value of A is
.
(a) Let J is the impulse does the engine exert on the rocket during the 4.0 s interval starting 2.00 s after the engine is fired. It is given in terms of force as :

Limits will be from 2 s to 2+ 4 = 6 s
It implies :

(b) Impulse is also equal to the change in momentum as :

Hence, this is the required solution.
What is it anyone answer it now