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valentinak56 [21]
3 years ago
11

PLEASE HELP use the image to answer the question. what is the name of the aluminum ion?

Physics
2 answers:
solong [7]3 years ago
8 0

<em>Answer:</em>

<em>Aluminum 3+</em>

<em>Sorry if im not correct</em>.

labwork [276]3 years ago
7 0

Answer:

Aluminium(3+)

Explanation:

im big brains

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The process of conversion of solid into gas and again gas into solid is known as
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Sublimation is when a solid becomes a gas.  And gas to solid is deposition.
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3 years ago
b. The stream of water flowing through a hole at depth h = 10 cm in a tank holding water to height H = 40 cm. . 3 At what distan
topjm [15]

Answer:

34.64 cm

Explanation:

Given that:

The depth of the hole h = 10 cm

height of the water holding in the tank H = 40 cm

For a stream of flowing water, the distance (x) at which the stream strikes the floor can be  computed by using the formula;

x = 2 \sqrt{h(H-h)}

x = 2 \sqrt{10(40-10)}

x = 2 \sqrt{10(30)}

x = 2 \sqrt{300}

x = 2 \times 17.32

x = 34.64 cm

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3 years ago
How can water play a role in chemical weathering
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3 years ago
A particle of mass m moves under a conservative force with potential energy V ( x )= cx/(x2+a2),where c and a are positive const
Anvisha [2.4K]

Answer:

The position of stable equilibrium is -a

And the period of small oscillations  must be: c/(ma^3)

Explanation:

Since the potential is:

V(x) = \frac{c x}{a^2+x^2}

We first look for a position of stable equilibrium. This posiiton must satisfy two considtions, that the first derivative of the potential must vanish at this point and the second derivative must be positive.

V'(x) = \frac{c}{a^2+x^2}-\frac{2 c x^2}{\left(a^2+x^2\right)^2}

Which vanish for

x = a   ; x =-a

The second derivative of V(x) is:

V''(x) = \frac{8 c x^3}{\left(a^2+x^2\right)^3}-\frac{6 c x}{\left(a^2+x^2\right)^2}

And:

V''(a) = -\frac{c}{2 a^3}\\V''(-a) = \frac{c}{2 a^3}\\

Therefore:

a)

The position of stable equilibrium is -a

And the period of small oscillations  must be:

\omega = \sqrt{2 V''(-a)/m} = \sqrt{\frac{c}{a^3 m}}

(c/(ma^3))^1/2

b)

Let's find the maximum amplitude if the particle starts at this point with velocity v

If this is the case, the total energy will be:

(mv^2)/2

And the maximum amplitude will be

x = a^3/c mv^2 = (m v^2 a^3)/ c

7 0
4 years ago
When looking at a distance-time graph, how could you tell who was the fastest without having to do any math?
Sholpan [36]

Explanation:

The speed of an object can be found from the slope of the line which plots its distance over time. The object in motion's speed can be compared with another by the value of the slope or the steepness of the line. The steeper the slope is, the greater the speed.

3 0
3 years ago
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