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3 years ago

Pls help me quick im doing a quiz

Physics

2 answers:

yawa3891 [41]3 years ago

7 0

Answer): A

I sorry if it is wrong

Katyanochek1 [597]3 years ago

6 0

ANSWER : 0.19 kilograms m/s south

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The type of image formed by a concave mirror depends on whether a reflected object is located ________________ the focal point a

Inga [223]

The answer to fill in the blank is between.

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4 years ago

A ball is thrown vertically upward from a height of 6 feet with an initial velocity of 41 feet per second. how high will the bal

maksim [4K]

Given: Height h = 6 ft or the vertical component "y" this become the initial height, therefore if you want to know the total height of the stone with respect to the ground. you can just add up the two value below.

Initial Velocity Vi = 41 ft/s g = -32.2 ft/s² acting downward

Require: Height h = ?

Formula: y = Vf² - Vi²/2g

y = 0 - (41 ft/s)²/2(-32.2 ft/s²)

y = -1,681 ft²/s²/(-64.4 ft/s²)

y = 26.10 ft

8 0

3 years ago

Light travels approximately 982,080,000 ft/s, and one year has approximately 32,000,000 seconds. A light year is the distance li

Anastasy [175]

Answer: 3.142656 × 10^16 feet

Explanation: Given that the

Speed = 982,080,000 ft/s, and

Time = 32,000,000 seconds

The formula for speed is:

Speed = distance/ time

Make distance the subject of formula

Since the time is second in one year and speed is ft/s, substitute both into the formula

Distance = speed × time

distance = 982,080,000 × 32,000,000

Distance = 3.142656 × 10^16 feet.

The distance of one light year in feet is 3.142656 × 10^16

8 0

3 years ago

Explain how hydrogen is changed to helium during fusion.

nadya68 [22]

Answer:

The Sun and Nuclear Fusion. In the core of the Sun hydrogen is being converted into helium. This is called nuclear fusion. It takes four hydrogen atoms to fuse into each helium atom

Explanation:

hop it helps

7 0

3 years ago

A rectangular tank that is 4 feet long, 2 feet wide and 15 feet deep is filled with a heavy liquid that weighs 60 pounds per cub

V125BC [204]

Answer:

a) W₁ = 54000 Lb-ft

b) W₂ = 77760 Lb-ft

c) W₃ = 24000 Lb-ft

W₄ = 40560 Lb-ft

Step by step

W= ∫₁² ydF 1 and 2 are the levels of liquid

Where dF is the differential of weight of a thin layer

y is the height of the differential layer and

ρ*V = F

Then

dF = ρ* A*dy*g

ρ*g = 60 lb/ft³

A= Area of the base then

Area of the base is:

A(b) = 4*2 = 8 ft²

Now we have the liquid weighs 60 lb/ft³

Then the work is:

W₁ = ∫₀¹⁵ 8*60*y*dy ⇒ W₁ =480* ∫₀¹⁵ y*dy

W₁ =480* y² /2 |₀¹⁵ ⇒ 480/2 [ (15)² - 0 ]

W₁ = 240*225

W₁ = 54000 Lb-ft

b) The same expression, but in this case we have to pump 3 feet higher, then:

W₂ = ∫₀¹⁸ 480*y*dy ⇒ 480*∫₀¹⁸ydy ⇒ 480* y²/2 |₀¹⁸

W₂ = 480/2 * (18)²

W₂ = 240*324

W₂ = 77760 Lb-ft

c) To pump two-thirds f the liquid we have

2/3* 15 = 10

W₃ = 480*∫₀¹⁰ y*dy ⇒ W₃ = 480* y²/2 |₀¹⁰

W₃ = 240*(10)²

W₃ = 24000 Lb-ft

W₄ =480*∫₀¹³ y*dy

W₄ =480* y²/2 |₀¹³

W₄ = 240*(13)²

W₄ = 240*169

W₄ = 40560 Lb-ft

3 0

3 years ago