The equation for electrical power is<span>P=VI</span>where V is the voltage and I is the current. This can be rearranged to solve for I in 6(a).
6(b) can be solved with Ohm's Law<span>V=IR</span>or if you'd like, from power, after substituting Ohm's law in for I<span>P=<span><span>V2</span>R</span></span>
For 7, realize that because they are in parallel, their voltages are the same.
We can find the resistance of each lamp from<span>P=<span><span>V2</span>R</span></span>Then the equivalent resistance as<span><span>1<span>R∗</span></span>=<span>1<span>R1</span></span>+<span>1<span>R2</span></span></span>Then the total power as<span><span>Pt</span>=<span><span>V2</span><span>R∗</span></span></span>However, this will reveal that (with a bit of algebra)<span><span>Pt</span>=<span>P1</span>+<span>P2</span></span>
For 8, again the resistance can be found as<span>P=<span><span>V2</span>R</span></span>The energy usage is simply<span><span>E=P⋅t</span></span>
Answer:
2,38kg
Explanation:
Mass in function of time can be found by the formula:
, where
is the initial mass, t is the time and k is a constant.
Given that a sample decay 1% per day, that means that after first day you have 99% of mass.
, but
, so we have
, then 
Now using k found we must to find
.

Answer:
28 degree C
Explanation:
We are given that




We have to find the temperature on a spring day when resistance is 215.1 ohm.
We know that

Using the formula




Hence, the temperature on a spring day 28 degree C.
Answer:d
Explanation:
Given systems are state of matter and do not contain any heat instead Heat is required to change Phase or raise the temperature of the particular system.
For example 600 kg of ice at 
Heat Required to convert it to water at
is

Where L=latent heat of Fusion 

