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mina [271]
3 years ago
11

What are two layers that can stop beta radiation?

Physics
1 answer:
tamaranim1 [39]3 years ago
5 0

<em><u>Answer:</u></em>

<em><u>Answer:They travel farther in air than alpha particles, but can be stopped by a layer of clothing or by a thin layer of a substance such as aluminum.</u></em>

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Help me plz it physics​
lesantik [10]
With what you do need help?????
7 0
4 years ago
Define investigation to show its scientific meaning.
Murrr4er [49]

Answer:

the action of investigating something or someone; formal or systematic examination or research.

Explanation:

This definition is provided by Oxford Languages

7 0
3 years ago
A cyclist makes the following trip along two vectors; he travels 9km to the north and then travels 6km to the east​
elena-14-01-66 [18.8K]

Answer:

Final distance from the origin: 10.82 km. the vector points as shown in the attached image.

Angle with respect to the east: 56.31^o

Explanation:

Please refer to the attached image. The cyclist's trip is indicated with the green arrows (9 km to the north followed by 6 km to the east.

So his final position is at the tip of this last vector, and indicated by the orange vector drawn form the point where the trip starts to the cyclist's final location.

We observe that this orange vector is in fact the hypotenuse of a right angle triangle, and we can estimate the distance from the origin by the Pythagorean theorem:

d=\sqrt{9^2+6^2} \\d=\sqrt{81+36} \\d=\sqrt{117} \\d=10.82 \,\,km

Notice that this is NOT the actual number of km that the cyclist pedaled to reach the final point.

Now, to find the value of the angle \theta, we need to use trigonometry, and in particular the tangent function gives us the ratio between the side of the triangle "opposite" to the angle, divided the side "adjacent" to the angle:

tan(\theta)=\frac{opp}{adj} \\tan(\theta)=\frac{9}{6}\\tan(\theta)=\frac{3}{2}\\

Now we can find the value of the angle by using the arctan function:

tan(\theta)=\frac{3}{2} \\\theta=arctan(\frac{3}{2} )\\\theta= 56.31^o

6 0
3 years ago
A ball which is dropped from the top of a building strikes the ground with a speed of 30m/s. Assume air resistance can be ignore
Vika [28.1K]

Answer:

               h= 45.87 m.

Explanation:

Data given:

Vf= 30m/s ,     and we know that g = 9.8 m/s²    

The ball has an initial velocity of zero      Vi = 0 m/s²    

To Find:

Height of the building = ?

Solution:

       According to 3rd law of the motion;

                                      2aS= Vf² - Vi²                      ( S= h , a=g)

                                     2*9.81*h = (30)² - (0)²

                                      h= 45.87 m.

3 0
3 years ago
Hey Jatin .
snow_tiger [21]

Answer:

what? i cant understand  you pls translate in English

6 0
4 years ago
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