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Vladimir [108]
3 years ago
6

A carousel has a diameter of 6.0-m and completes one rotation every 1.7s. Find the centripetal acceleration of the traveler in m

/ s2.
Physics
1 answer:
Anestetic [448]3 years ago
4 0

Answer:

The centripetal acceleration of the traveler is 40.98\ m/s^2

Explanation:

It is given that, A carousel has a diameter of 6.0-m and completes one rotation every 1.7 s.

We need to find the centripetal acceleration of the traveler. It is given by the formula as follows :

a=\dfrac{v^2}{r}

r is radius of carousel

v=\dfrac{2\pi r}{T}

So,

a=\dfrac{4\pi ^2r}{T^2}

Plugging all the values we get :

a=\dfrac{4\pi ^2\times 3}{(1.7)^2}\\\\a=40.98\ m/s^2

So, the centripetal acceleration of the traveler is 40.98\ m/s^2.

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A source vibrating at constant frequency generates a sinusoidal wave on a string under constant tension. If the power delivered
Serjik [45]

Answer:

n = 1,732    the amplitude must be increased by a factor of 1,732

Explanation:

The power delivered by a wave is given by

                  P = E / t

                  P = ½ μ w² v A²

let's apply this expression to our case the power tripled

                3P₀ = ½ μ w² v A’²

                 

let's write the amplitude function of a initial amplitude

               A ’= n A₀

where n is a number

               3 P₀ = (½ μy w² v  A₀²) n²

               3P₀ = P₀ n²

               n = √ 3

               n = 1,732

therefore the amplitude must be increased by a factor of 1,732

4 0
3 years ago
You walk 60m east and then 20m at 20 degrees south of west. What is your displacement?
stich3 [128]
Let north and east be posetive
Y=20sin20
=6.840402867 south
X=20cos20
18.79385243 west
Net horizontal components=60+(-18.79)
=41.20614758m
Net vertical=-6.84040267
X^2=41.20614758^2+(-6.684040267)^2
√x^2 =√1744.73771m
x=41.77m
5 0
3 years ago
A crude approximation is that the Earth travels in a circular orbit about the Sun at constant speed, at a distance of 150,000,00
Savatey [412]

Answer:

The answer is "Option B".

Explanation:

r=15\times 10^{7}\ km\ = 15\times 10^{10}\ m\\\\w=\frac{2\pi}{1\ year}\\\\=\frac{2\pi}{1\times 365.24 \times 24 \times 60 \times 60\ sec}\\\\a=w^2r\\\\=(\frac{2\pi}{1\times 365.24 \times 24 \times 60 \times 60\ sec})^2 \times 15 \times 10^{10}\ \frac{m}{s^2}\\\\

=5.940 \times 10^{-3} \ \frac{m}{s^2}\\\\=6 \times 10^{-3} \ \frac{m}{s^2}\\\\=0.006\ \frac{m}{s^2}\\\\

7 0
3 years ago
Most metals are in the liquid state at room temperature.
aivan3 [116]

Answer:

Most metals are in the liquid state at room temperature.<u>False</u><u>.</u>

Explanation:

it needs excess heat except mercury and lithium.

4 0
3 years ago
Read 2 more answers
A conducting coil of 1850 turns is connected to agalvanometer, and the total resistance of the circuit is 45.0 ohm.The area of e
Xelga [282]

Answer:

0.459 Tesla

Explanation:

Faraday's law:

Emf = -N\frac{\delta\phi}{\delta t}

Φ= NAB

V =   N Δ (BA) /Δt      

the change in BA

was:    BA =  0   because initially B was zero.

V=IR

   IR =   N B A /Δt

   q / Δt ×R   =      N B A / Δt

Or:    B =   q R / NA = 8.87 x 10^-3 × 45.0 / 1850×4.7 x 10^-4 =

          = 0.459 Tesla

3 0
4 years ago
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