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vagabundo [1.1K]
3 years ago
9

a 2 kg laptop sits on the floor near a 4 kg jar of pennies. if the force of gravity between them is 3.42× 10⁻¹⁰ , how far apart

are they?
Physics
1 answer:
MissTica3 years ago
8 0

The answer is 1.25 m

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The graph indicates Linda’s walk.
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What are the precaution you take when you are carrying out experiment on kirchhoffs law​
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Answer:

The precautions to be followed for performing kirchoff law experiment are:-

  1. check that all the connections inside the arrangement are tight and clean.
  2. check that the terminals of the resistances  are nicely attached.
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Which of the following statements about the
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A gas within a piston–cylinder assembly undergoes a
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Answer:

W_{net}= -280.5 kJ

Q_{23}= 80.0 kJ

Explanation:

The net work of the cycle is the sum of works in each process.

<u>For the first process 1-2: </u> Let's apply the work definition.

W=\int pdV (1)

Now, we need the pressure. We know that pV=C, where C is a constant. Then  p_{1}V_{1}=10^{5}2=2*10^{5} [J]

So p=\frac{2*10^{5}}{V}

Let's put p in (1):

W_{12}=\int \frac{2*10^{5}}{V}dV=2*10^{5}\int \frac{1}{V}dV

W_{12}=2*10^{5}(ln(V_{2})-ln(V_{1}))=2*10^{5}(ln(0.2)-ln(2))=-460.5 kJ

Using the first law of thermodynamics we can find Q.

Q_{12}-W=\Delta U

Q_{12}=W+\Delta U=-460.5 + 100= -360.5 kJ

<u>Second process 2-3</u>

In this case, we have a constant volume, so the work done here is 0.

W_{23}=0

<u>Third process 3-1</u>

W_{31}=\int pdV=p\int dV=p(V_{2}-V_{1})

W_{31}=10^{5}(2-0.2)=180 kJ

Finally, the net work is:

W_{net}=W_{12}+W_{23}+W_{31}= -280.5 kJ

By the conservation of energy:

(Q_{12}+Q_{23}+Q_{31})-(W_{net})=\Delta E=0

Because there is no change in total energy.

So:

Q_{23}=W_{net}-Q_{12}= 80.0 kJ

It is a refrigerator because the net work is negative, it means it consumes energy.

I hope it helps you!

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