Explanation:
The horizontal velocity reached by the mass is:
v = v₀ + at
vₓ = 0 + (F/m) (1 s − 0 s)
vₓ = F/m
The force is then removed, so the mass continues at this horizontal velocity.
The vertical velocity reached by the mass is:
v = v₀ + at
vᵧ = 0 + (F/m) (2 s − 1 s)
vᵧ = F/m
The force is then removed, so the mass continues at this vertical velocity.
So at 2 seconds, the mass's velocity has equal components in the x and y directions, and continues to have that velocity at 3 seconds.
I think thirst or dark colored urine. :)
The correct answer is: Velocity
The speed of the earth's surface located at 2/3 of the length of the arc between the pole which measure from the equator is 232.5 m/s.
Solution:
So the givens are, earth's radius = 6.37X10^6m, and the angular distance from the pole is 90 degrees. So 60 degrees is the 2/3.
r = 6.37x10^6 * cos(60) = 3.185x10^6m
since v = wr
v = 7.3x10^-5 * 3.185x10^6
v - 232.5 m/s
Find out what the force is and yiy have your answer
