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iren [92.7K]
4 years ago
13

In order to get going fast, eagles will use a technique called stooping, in which they dive nearly straight down and tuck in the

ir wings to reduce their surface area. While stooping, a 6- kg golden eagle can reach speeds of up to 53 m/s . While golden eagles are not very vocal, they sometimes make a weak, high-pitched sound. Suppose that while traveling at maximum speed, a golden eagle heads directly towards a pigeon while emitting a sound at 1.1 kHz. The emitted sound has a sound intensity level of 30 dB when heard at a distance of 5 m .
Part A: Not So Free Fallin’

Model this stooping golden eagle as an object moving at terminal velocity. The eagle’s drag coefficient is 0.5 and the density of air is 1.2 kg/m 3 . What is the effective cross-sectional area of the eagle’s body while stooping?

Part B: The Doppler Effect

What is the doppler-shifted frequency that the pigeon will hear coming from the eagle?

Part C: Dangerous Decibels?

Consider the moment when the pigeon is 5 m away from the eagle. At the pigeon’s position, what is the intensity (in W/m 2 ) of the sound the eagle makes?

Part D: The Catch

The golden eagle slams into the 250- g pigeon, which is initially moving at 10 m/s in the opposite direction (toward the eagle). The eagle grabs the pigeon in its talons, and they move off together in a perfectly inelastic collision. How fast do they move after the collision?
Physics
2 answers:
polet [3.4K]4 years ago
7 0

Answer:

the anwser is The healthy adult golden eagle, due to its impressive size and hunting prowess, has no natural predators. Eggs, chicks, immature eagles, and injured birds are susceptible to a range of predators, such as other birds of prey, including other kinds of eagles and hawks, bears, wolves and cougars.

Explanation:

Scilla [17]4 years ago
3 0

Answer: the anwser is The healthy adult golden eagle, due to its impressive size and hunting prowess, has no natural predators. Eggs, chicks, immature eagles, and injured birds are susceptible to a range of predators, such as other birds of prey, including other kinds of eagles and hawks, bears, wolves and cougars.

Explanation:

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A 16 g piece of Styrofoam carries a net charge of -8.6 µC and floats above the center of a large horizontal sheet of plastic tha
PilotLPTM [1.2K]

Answer:

the charge per unit area on the plastic sheet is - 3.23 x 10⁻⁷ C/m²

Explanation:

given information:

styrofoam mass, m = 16 g = 0.016 kg

net charge, q = - 8.6 μC

to calculate the charge per unit area on the plastic sheet, we can use the following equation:

F_{e} = mg

where

F_{e} = the force between the electric field

m = mass

g = gravitational force

F_{e} =qE

where

q = charge

E = electric field

and

E = σ/2ε₀

where

ε₀ = permitivity

thus

F_{e} =qE

mg = qσ/2ε₀

σ = (2mg ε₀)/q

  = 2 (0.016) (9.8)  (8.85 x 10⁻¹²)/( - 8.6 x 10⁻⁶)

  = - 3.23 x 10⁻⁷ C/m²

8 0
4 years ago
The shortstop plays between first and second base.<br> true or false
adell [148]

SINGLE TO RIGHT OR CENTER FIELD-On a single to center or right field the first baseman will be the cutoff to home. The shortstop will cover second base.

4 0
3 years ago
Which of the Jovian planets have rings?
stira [4]
Jupiter , Saturn , Uranus , Neptune .
7 0
3 years ago
Read 2 more answers
Review. As an astronaut, you observe a small planet to be spherical. After landing on the planet, you set off, walking always st
anyanavicka [17]

To find the mass of the planet we will apply the relationship of the given circumference of the planet with the given data and thus find the radius of the planet. From the kinematic equations of motion we will find the gravitational acceleration of the planet, and under the description of this value by Newton's laws the mass of the planet, that is,

The circumference of the planet is,

\phi = 25.1m

Under the mathematical value the radius would be

\phi = 2\pi r

r = \frac{25}{2\pi}

r = 3.9788km

Using second equation of motion

x = \frac{1}{2} at^2

Replacing the values given,

1.4 = \frac{1}{2} a (29.2)^2

Rearranging and solving for 'a' we have,

a = 0.003283m/s^2

Using the value of acceleration due to gravity from Newton's law we have that

a = \frac{GM}{r^2}

Here,

r = Radius of the planet

G = Gravitational Universal constant

M = Mass of the Planet

\frac{(6.67*10^{-11})*M}{(3.9788*10^3)^2} = 0.003283

M = 7.79201*10^{14}kg

Therefore the mass of this planet is 7.79201*10^{14}kg

5 0
4 years ago
6. The first vertebrates appeared during
RUDIKE [14]

Answer:

b. the Paleozoic Era

Explanation:

The first vertebrates to appear are primitive fish in the Cambrian Period, but bony fishes with actual bony vertebratae didn't appear for another 100 million years. The Cambrian Period is the first of three periods in the Paleozoic Era. The Cambrian explosion was an event when practically all major animal phyla started appearing in the fossil record.

6 0
2 years ago
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