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iren [92.7K]
4 years ago
13

In order to get going fast, eagles will use a technique called stooping, in which they dive nearly straight down and tuck in the

ir wings to reduce their surface area. While stooping, a 6- kg golden eagle can reach speeds of up to 53 m/s . While golden eagles are not very vocal, they sometimes make a weak, high-pitched sound. Suppose that while traveling at maximum speed, a golden eagle heads directly towards a pigeon while emitting a sound at 1.1 kHz. The emitted sound has a sound intensity level of 30 dB when heard at a distance of 5 m .
Part A: Not So Free Fallin’

Model this stooping golden eagle as an object moving at terminal velocity. The eagle’s drag coefficient is 0.5 and the density of air is 1.2 kg/m 3 . What is the effective cross-sectional area of the eagle’s body while stooping?

Part B: The Doppler Effect

What is the doppler-shifted frequency that the pigeon will hear coming from the eagle?

Part C: Dangerous Decibels?

Consider the moment when the pigeon is 5 m away from the eagle. At the pigeon’s position, what is the intensity (in W/m 2 ) of the sound the eagle makes?

Part D: The Catch

The golden eagle slams into the 250- g pigeon, which is initially moving at 10 m/s in the opposite direction (toward the eagle). The eagle grabs the pigeon in its talons, and they move off together in a perfectly inelastic collision. How fast do they move after the collision?
Physics
2 answers:
polet [3.4K]4 years ago
7 0

Answer:

the anwser is The healthy adult golden eagle, due to its impressive size and hunting prowess, has no natural predators. Eggs, chicks, immature eagles, and injured birds are susceptible to a range of predators, such as other birds of prey, including other kinds of eagles and hawks, bears, wolves and cougars.

Explanation:

Scilla [17]4 years ago
3 0

Answer: the anwser is The healthy adult golden eagle, due to its impressive size and hunting prowess, has no natural predators. Eggs, chicks, immature eagles, and injured birds are susceptible to a range of predators, such as other birds of prey, including other kinds of eagles and hawks, bears, wolves and cougars.

Explanation:

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How long does it take oxygen to diffuse a distance of 1 mm in water at room temperature? How long does it take oxygen to diffuse
Viktor [21]

Answer:

option A

Explanation:

given,

travel distance = 1 mm

diffusion constant for the  molecule  of oxygen in water = 1 x 10⁻⁹ m²/s

we know that

 t = \dfrac{x^2}{2D}

t is the time taken for diffusion

x = 1 mm = 10⁻³ m

D is the diffusion

 t = \dfrac{(10^{-3})^2}{2\times 10^{-9}}

 t = \dfrac{(10^{3})}{2}

        t = 500 s

so, the option to the answer is 170 s

the correct answer is option A

8 0
4 years ago
A stuntman drives a car with a mass of 1500 kg on a drawbridge. The car accelerates with a constant force of 10,000 N. While he
Viktor [21]

Answer:

1.77 m/s^2

Explanation:

There are two forces acting on the car along the direction parallel to the incline:

- The driving force of 10,000 N, which pushes forward

- The component of the weigth of the car parallel to the incline, which pulls backward

The component of the weight of the car parallel to the incline is:

W_p = mg sin \theta=(1500 kg)(9.8 m/s^2)( sin 30^{\circ})=7350 N

So now we can apply Newton's second law to find the acceleration of the car:

F-W_p = ma\\a=\frac{F-W_p}{m}=\frac{10000 N-7350 N}{1500 kg}=1.77 m/s^2

7 0
3 years ago
Minions are a happy color yellow. Which of the following statements about minions is correct?
likoan [24]
D all of the above
Hope it helps
6 0
3 years ago
How to represent milligram in kilogram by standard formula?
Anettt [7]

Answer:

0.000001 kg

Explanation:

because 1 kg equal 1,000,000 milligrams

we take   \frac{1}{1,000,000} which equals 0.000001 kg

4 0
3 years ago
A 2cm length of wire centered on the origin carries a 20A current directed in the positive y direction. Determine the magnetic f
skad [1K]

Answer:

The magnetic field at a distance x = 5 m is 1.59 nT

Explanation:

Length of the wire, L = 2 cm = 0.02 m

Current, I = 20 A

x = 5 m

Magnetic field at a distance x = 5 m due to an infinitely long wire is given by:

B = \frac{\mu_{o}IL}{4\pi x\sqrt{x^{2} + L^{2}}}

B = \frac{4\pi\times 10^{- 7}\times 20\times 0.02}{4\pi \times 5\sqrt{5^{2} + 0.02^{2}}} = 1.59\times 10^{- 9}\ T

3 0
3 years ago
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