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Kitty [74]
3 years ago
9

What is one group of people or animals that are impacted by ocean acidification?

Chemistry
2 answers:
Andrej [43]3 years ago
8 0
Plankton, corals, shellfish, sea urchins
ki77a [65]3 years ago
6 0

Answer:

Impacts on Ocean Life

Coral Reefs.

Oysters, Mussels, Urchins and Starfish.

Zooplankton.

Plants and Algae.

Fish.

Explanation:

You might be interested in
5.25 ml of substance A has a mass of 3.9 g and 6.24 ml of substance B has a mass of 4.4 g. Which liquid is more dense?
Viktor [21]
Substance A because it weighs less
5 0
3 years ago
Water that flows back to the ocean is called
nordsb [41]

Surface runoff

Explanation:

The water that flows back to the streams and oceans are called surface runoff.

Surface runoff is a component of the water cycle usually composed of water in the liquid form that flows back into oceans that are nearby.

  • The hydrologic cycle shows the cyclic process by which water passes in nature.
  • Water passes through different forms, solid, liquid and gases.
  • Surface runoff is water usually after rainfall that flows rapidly.
  • They move to the final basin of deposition usually joining up with other water sources.
  • This can be nearby streams, lakes or oceans.

learn more:

Downcutting a stream brainly.com/question/9259211

#learnwithBrainly

4 0
4 years ago
A 33.0−g sample of an alloy at 93.00°C is placed into 50.0 g of water at 22.00°C in an insulated coffee-cup calorimeter with a h
Lostsunrise [7]

Answer:

THE SPECIFIC HEAT OF THE ALLOY IS 0.9765 J/g K

Explanation:

Mass of alloy = 33 g

Initial temperature of alloy = 93°C

Mass of water = 50 g

Initail temp. of water = 22 °C

Heat capacity of calorimeter = 9.20 J/K

Final temp. = 31.10 °C

specific heat of alloy = unknown

specific heat capacity of water = 4.2 J/g K

Heat = mass * specific heat * change in temperature = m c ΔT

Heat = heat capcity * chage in temperature = Δ H * ΔT

In calorimetry;

Heat lost by the alloy = Heat gained by water + Heat of the calorimeter

                     mc ΔT = mcΔT + Heat capacity * ΔT

33 * C * ( 93 - 31.10) = 50 * 4.2 * ( 31.10 -22) + 9.20 * ( 31.10 -22)

33 * C * 61.9 = 50 * 4.2 * 9.1 + 9.20 * 9.1

2042.7 C = 1911 + 83,72

C = 1911 + 83.72 / 2042.7

C = 1994.72 /2042.7

C =0.9765 J/g K

The specific heat of the alloy is 0.9765 J/ g K

5 0
3 years ago
What is the maximum amount of kcl that can dissolve in 200 g of water? (the solubility of kcl is 34 g/100 g h2o at 20°c.) (1 poi
Solnce55 [7]
The answer is 68g
hope this helps!!
5 0
4 years ago
How much mass of sodium chloride ( ) should be dissolved in water to make 1.5 L of 0.75 M aqueous solution? The molar mass of is
iogann1982 [59]

Answer:

Mass = 65.8 g

Explanation:

Given data:

Mass of sodium chloride = ?

Volume of solution = 1.5 L

Molarity of solution = 0.75 M

Solution:

Number of moles of sodium chloride:

Molarity = number of moles / volume in L

By putting values,

0.75 M = number of moles = 1.5 L

Number of moles = 0.75 M × 1.5 L

Number of moles = 1.125 mol

Mass of sodium chloride:

Mass = number of moles × molar mass

Mass = 1.125 mol × 58.5 g/mol

Mass = 65.8 g

4 0
2 years ago
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