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Irina18 [472]
2 years ago
8

Atmospheric pressure decreases as altitude increases. In other words, there is more air pushing down on you at sea level, and th

ere is less air pressure pushing down on you when you are on a mountain.If pentane (C5H12), hexane (C6H14), and hexanol (C6H13OH) are heated evenly at different altitudes, rank them according to the order in which you would expect them to begin boiling.
1. Hexane high altitude.
2. Pentane high altitude.
3. Hexane sea level.
4. Hexanol sea level
Chemistry
1 answer:
Gekata [30.6K]2 years ago
8 0

Answer:

step 2 then step 1 then step 3 then step 4

Explanation:

First boil it. Then identify the situation which is most conducive to boiling .

While this, a liquid must overcome the attractive forces between molecules and the outside pressure pushing down on the liquid's surface.

The liquid will boil when there is weak intermolecular attraction and low atmospheric pressure.

Steps to be followed:

Pentane at high altitude

Hexane at high altitude

hexane at sea level

hexanol at sea level

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IF ANSWER I WILL GIVE BRAINLESS
vovikov84 [41]

Answer:

Answer 9 - 100 joules energy was at the producer level

Answer 10 - Remaining energy is used in metabolism

Explanation:

Answer 9

The energy at each trophic level is only 10% of the energy at its previous trophic level.

The energy at producer level is X

10 % of X = 10 Joules

\frac{10}{100} * X = 10\\X = 100Joules

Answer 10

Because the remaining 90% energy is utilized by the producer for its metabolism

3 0
2 years ago
The total pressure of gases a, b, and c in a closed container is 4.1 atm. if the mixture is 36% a, 42% b, and 22% c by volume, w
Natali [406]

 The  partial  pressure of  gas C  is 0.902  atm


  calculation

partial pressure of gas c  =[( percent by volume of  gas   C /  total  percent)   x total pressure]


percent  by  volume of gas C= 22%

Total   percent  = 36% +42%  + 22%  = 100 %

Total  pressure  =  4.1 atm


partial  pressure  of gas C  is therefore =  22/100 x 4.1 atm = 0.902  atm

3 0
3 years ago
Read 2 more answers
When 16.0 g of an unknown compound (a nonelectrolyte) are dis solved in exactly 800. g of water, the solution has a freezing poi
dexar [7]

Answer:

A. 266g/mol

Explanation:

A colligative property of matter is freezing point depression. The formula is:

ΔT = i×Kf×m <em>(1)</em>

Where:

ΔT is change in temperature (0°C - -0,14°C = 0,14°C)i is Van't Hoff factor (1 for a nonelectrolyte dissolved in water), kf is freezing point molar constant of solvent (1,86°Cm⁻¹) and m is molality of the solution (moles of solute per kg of solution). The mass of the solution is 816,0g

Replacing in (1):

0,14°C = 1×1,86°Cm⁻¹× mol Solute / 0,816kg

<em>0,0614 = mol of solute</em>.

As molar mass is defined as grams per mole of substance and the compound weights 16,0g:

16,0g / 0,0614 mol = 261 g/mol ≈ <em>A. 266g/mol</em>

I hope it helps!

3 0
2 years ago
The equilibrium constant for the gas phase reaction N2 (g) + O2 (g) ⇌ 2NO (g) is Keq = 4.20 ⋅ 10-31 at 30 °C. At equilibrium, __
pychu [463]

Answer:

At equilibrium, reactants predominate.

Explanation:

For every reaction, the equilibrium constant is defined as the ratio between the concentration of products and reactants. Thus, for the reaction N2 (g) + O2 (g) ⇌ 2NO the expression of its equilibrium constant is:

Keq = \frac{[NO]^{2}}{[O_{2} ][N_{2}]}

Since the equilibrium constant is Keq = 4.20x10-31 the concentration of reactants O2 and N2 must be much higher than products to obtain such a small number as  4.20x10-31 at the equilibrium. Hence, at equilibrium reactants predominate.

5 0
3 years ago
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Methanol (CH3OH) has a heat of fusion of 3.16 kJ/mol. Which of the following is the heat of solidification that occurs when 64 g
Alexandra [31]
To determine the heat dissipated when a substance freezes, we multiply the heat of fusion of the substance to the mass of the substance that freezes. We calculate as follows:

Heat = -3.16 (64/32.06) = - 6.32 kJ

Hope this answers the question.
5 0
3 years ago
Read 2 more answers
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