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galina1969 [7]
3 years ago
7

10. There are two bears that both have the same proteins for ear shape in their cells. The bears have

Chemistry
2 answers:
lapo4ka [179]3 years ago
8 0

Answer:

They will have the same ear shape since their proteins connect in the same ways to determine ear shape.

Explanation:

valentinak56 [21]3 years ago
4 0

Answer:

They will have the same ear shape since their proteins connect in the same ways to determine ear shape.

Explanation:

I majored in Chemistry

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Write a balanced half-reaction for the reduction of bismuth oxide ion to bismuth ion in basic aqueous solution. Be sure to add p
Butoxors [25]

Answer:

3H_2O+(Bi^{5+}O_3)^-\rightarrow Bi^{3+}+6OH^-

Explanation:

Hello there!

In this case, according to the required half-reaction, we start by setting it up from bismuth (V) oxide ion to bismuth (III) ion:

BiO_3^-\rightarrow Bi^{3+}

Thus, next realize that the oxidation state of Bi in BiO3^- is 5+ because oxygen is 2- (-2*3+x=-1;x=-1+6;x=+5), so we obtain:

(Bi^{5+}O_3)^-\rightarrow Bi^{3+}

Thereafter, we realize three water molecules are needed on the right in order to balance the oxygens and consequently 6 hydrogen atoms on the left to balance hydrogen:

6H^++(Bi^{5+}O_3)^-\rightarrow Bi^{3+}+3H_2O

Now, since the balance is is basic media, we add six molecules of hydroxide ions in order to produce water with the hydrogen ones:

6OH^-+6H^++(Bi^{5+}O_3)^-\rightarrow Bi^{3+}+3H_2O+6OH^-\\\\6H_2O+(Bi^{5+}O_3)^-\rightarrow Bi^{3+}+3H_2O+6OH^-\\\\6H_2O-3H_2O+(Bi^{5+}O_3)^-\rightarrow Bi^{3+}+6OH^-

Then, we accommodate the waters to obtain:

3H_2O+(Bi^{5+}O_3)^-\rightarrow Bi^{3+}+6OH^-

Best regards!

7 0
3 years ago
Calculate the concentration (in mol/l) of 33% by weight (33 g naoh per 100 g of solution) naoh solution. (the density of the 33%
Shtirlitz [24]
Molarity is measured in moles per Liter. If there are 1.35 g/mL, find out how many grams there are in a liter of solution.

If there are 1000 mL in one liter, we can multiply by 1000 to get g/L

1.35 g/mL x 1 Liter/1000 mL = 1350 g per Liter of solution

By weight, the NaOH is 33% or .33

1350 g x .33 = 445.5 g of NaOH

Molar mass of NaOH is 39.997 g

445.5 g  x 1 mol NaOH/39.997 g = 11.13833538 moles per Liter

Rounded to significant figures, the answer is 11 mol/L NaOH


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Answer:

who da hell is cassady?

Explanation:

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There are a lot of ways to increase the solubility of the solute. <span>Increasing the temperature, mixing time and surface area of a solvent increases the solubility of the solute</span>
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