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serg [7]
3 years ago
11

How is the potential (voltage) of a redox reaction determined using the reduction

Chemistry
1 answer:
LuckyWell [14K]3 years ago
6 0

Answer:

caused by the ability of electrons to flow from one half cell too the other

Explanation:

How is the potential voltage of a redox reaction?

The potential difference is caused by the ability of electrons to flow from one half cell to the other. Electrons are able to move between electrodes because the chemical reaction is a redox reaction. A redox reaction occurs when a certain substance is oxidized, while another is reduced.

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What are the advantages and disadvantages of using an egg to model organelles in an animal c of using an egg to model organelles
aleksandrvk [35]
I think its because an egg doesnt have the right chemical make up
7 0
3 years ago
Pls help because im not smart.-.
tangare [24]

Answer:

Im not smart either but im pretty sure its D because its a pie chart so its asking how many and pie charts tell you how much something has

Explanation:

3 0
2 years ago
Read 2 more answers
A mixture of gaseous sulfur dioxide and oxygen are added to a reaction vessel and heated to 1000 K where they react to form SO3
nasty-shy [4]

Answer:

Kp = 0.0410

Explanation:

The reaction of gaseous sulfur dioxide and oxygen to form SO3 (g) is:

2SO₂(g) + O₂(g) ⇄ 2SO₃(g)

Kp is defined as the ratio of pressure of products and pressure of reactants:

Kp = \frac{P_{SO_3}^2}{P_{SO_2}^2P_{O_2}}

Kp = \frac{0.0851atm^2}{0.669atm^2*0.395atm}

Kp = 0.0410

I hope it helps!

5 0
3 years ago
The 10x SDS gel electrophoresis buffer contains 250mM Tris HCl, 1.92M Glycine, and 1% (w/v) SDS. Buffers are always used at 1x c
olchik [2.2K]

Answer:

25 mM Tris HCl and 0.1% w/v SDS

Explanation:

A <em>10X solution</em> is ten times more concentrated than a <em>1X solution</em>. The stock solution is generally more concentrated (10X) and for its use, a dilution is required. Thus, to prepare a buffer 1X from a 10X buffer, you have to perform a dilution in a factor of 10 (1 volume of 10X solution is taken and mixed with 9 volumes of water). In consequence, all the concentrations of the components are diluted 10 times. To calculate the final concentration of each component in the 1X solution, we simply divide the concentration into 10:

(250 mM Tris HCl)/10 = 25 mM Tris HCl

(1.92 M glycine)/10 = 0.192 M glycine

(1% w/v SDS)/10 = 0.1% w/v SDS

Therefore the final concentrations of Tris and SDS are 25 mM and 0.1% w/v, respectively.

7 0
3 years ago
What is the density of N2 gas (molar mass: 28 g/mol), at 400 K and 2 atm?
Olenka [21]

Answer:

Density= 1.7g/dm3

Explanation:

Applying

P×M= D×R×T

P= 2atm, Mm= 28, D=? R= 0.082, T= 400K

2×28= D×0.082×400

D= (2×28)/(0.082×400)

D= 1.7g/dm3

7 0
3 years ago
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