Answer : The molarity of 
in the solution is 1.5 M.
Explanation : Given,
Moles of = 3.0 mol
Volume of solution = 2.00 L
Molarity : It is defined as the number of moles of solute present in one liter of volume of solution.
Formula used :
Now put all the given values in this formula, we get:
Therefore, the molarity of in the solution is 1.5 M.
It shows mass is not created nor lost but re arranged
Answer:
1859.4 g of ZnCrO₄ in 10.25 moles
Explanation:
First of all, we determine the molecular formula of the compound:
Zinc → Zn²⁺ (cation)
Chromate → CrO₄⁻² (anion)
Zinc chromate → ZnCrO₄
Molar mass for the compound is:
Molar mass of Zn + Molar mass of Cr + (Molar mass of O) . 4 = 181.41 g/mol
65.41 g/mol + 52 g/mol + 16 g/mol . 4 = 181.41 g/mol
Let's apply this conversion factor: 10.25 mol . 181.41 g/mol = 1859.4 g
The Correct answer to this question is translation
The solution for this problem is:
C6H5NH3Cl is a strong salt: C6H5NH3+ + Cl- C6H5NH3+ + H2O <-----> C6H5NH2 + H3O+
K = Kw/ Kb= 1.0 x 10^-14 / 3.8 x 10^-10= 2.6 x 10^-5
=2.6 x 10^-5 = x^2 / 0.240-x
x = [H3O+] = 0.00251 M
pH = 2.60 is the concentration
