The type of nuclear decay in which Oxygen decays to form nitrogen is beta plus decay.
<h3>What is a beta plus decay?</h3>
A beta plus decay is a type of decay in which a proton in an element disintegrates to produce a neutron resulting in a decrease in the atomic number of the radioactive element.
In the given equation below:
Oxygen decays to form nitrogen due to a decrease in atomic number.
This is an example of beta plus decay.
In conclusion, oxygen decays to form nitrogen beta plus decay.
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Colligative
properties calculations are used for this type of problem. Calculations are as
follows:<span>
ΔT(freezing point) = (Kf)(molality)
ΔT(freezing point)
= 1.86 °C kg / mol (molality)
</span>Tf - 102.08 = 1.86m
Tf = 1.86m + 102.08
The concetration of the solution is needed in order to obtain a specific value.
Answer:
Ld₂Mz
General Formulas and Concepts:
<u>Chemistry - Compounds</u>
- Valence shells
- Writing chemical compounds
- Balancing charges
Explanation:
<u>Step 1: Define</u>
"Lindenium" Ld w/ oxidation charge of +1
"Mendezine" Mz w/ oxidation charge of -2
<u>Step 2: Write Compound</u>
To balance out the charges to be neutral (0), we must counter balance the amount of Ld's with Mz's. We need 2 Ld's with 1 Mz to create a compound with a neutral charge:
2Ld¹⁺ + Mz²⁻
2(+1) + (-2) = (+2) + (-2) = 0 (neutral charge)
Therefore, our compound must be Ld₂Mz.
Answer:- 9.4 minutes.
Solution:- Radioactive decay obeys first order reaction kinetics and the equation used to solve this type of problems is:
where, k is decay constant and t is the time. is the initial amount of the radioactive substance and N is the remaining amount.
Since the value of decay constant is not given, so we need to calculate it first from given half life by using the formula:
where stands for half life.
Given half life is 3.0 minutes.
So,
Let's plug in the values in the first order reaction equation and solve it for t.
It could also be written as:
k = 9.4 min
So, the radioactive substance would take 9.4 minutes to decay from 40.0 grams to 4.5 grams.