A student can take three subjects in 40 ways.
<u>SOLUTION:</u>
Given that, there are 4 different math courses, 5 different science courses, and 2 different history courses.
A student must take one of each, how many different ways can this be done?
Now, number ways to take math course = 4
Number of ways to take science course = 5
Number of ways to take history course = 2
So, now, total possible ways = product of possible ways for each course = 4 x 5 x 2 = 40 ways.
Hence, a student can take three subjects in 40 ways.
Answer:
3) 5.4
Step-by-step explanation:
Given two points (x1, f(x1)) and (x2, f(x2)), the average rate of change is computed as follows:
[f(x2) - f(x1)]/[x2 - x1]
From the original photograph to the fourth enlargement, the points are (0, 15) and (4, 36.6). Replacing into the equation we get:
[36.6 - 15]/[4 - 0] = 5.4
Answer:
the second description and and expression is correct
Step-by-step explanation:
the first one is wrong because it says 7 minus while it should be minus 7
Answer:
8
Step-by-step explanation:
1/6 of 12 is 2
12 - 2 = 10
1/5 of 10 is also 2
10 - 2 = 8
Tommy took 8 donuts to work.
Answer:
Step-by-step explanation:
