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Alchen [17]
3 years ago
9

\frac{30}{7}" alt="\frac{20+}{12-} \frac{30}{7}" align="absmiddle" class="latex-formula">
Mathematics
1 answer:
inysia [295]3 years ago
6 0

Answer:

the answer is 10

Step-by-step explanation:

hope this helps

You might be interested in
Let x represent one number and let y represent the other number. The sum of two numbers is negative 6. If one number is subtract
GalinKa [24]

Answer:

x=7 and y=-1

Step-by-step explanation:

X+Y=6 OR X=6-Y  ...(1)

X-Y=8    ...(2)

substitue X=6-Y in (2)

(6-Y)-Y=8

6-2Y=8

-2Y=8-6

-2Y=2

Y=2/-2\Y=-1 ANS.

for x, substitute Y=-1 in (1) above

X-(-1)=8

X=8-1

X=7 ANS.

7 0
3 years ago
Just need some help with math
V125BC [204]
Each pie/circle has 10 sections. there is 3 whole sections so you would do 10x3 is equal to 30.

then, there’s a fourth pie that has one unshaded section. so, that would be only 9. add the 30 and 9 and you would get 39.

so, for the one fraction, you would get 39/10.

for the mixed number, you get 3 9/10 because 10 goes into 39 3 times and then you have 9 left over.
4 0
2 years ago
1. What is the formula for compound interest?
Rus_ich [418]

Answer:

  1.   CI = P (1 + \frac{r}{100} )^ n - P

        CI = A - P

      Where P is Principal

      R is interest rate

      n is number of years

   2. a. Semi annually - four times in a year

       b. Monthly           -  two times in a year

       c.  annually          -  once in a year

Step-by-step explanation:

1.  Money is said to be lent at compound interest , when the interest has become due at certain fixed period say, one year, half year, etc.., is given not paid to money lender, but is added to sum lent . The amount thus obtained become principal for next month and this process repeat until last period .

i.e CI = Final period - Initial period

or CI = A - P

or CI = P(1+ \frac{r}{100}) ^n - P

2. (a) Semi annually

        A = P (1 + \frac{r}{4 * 100} )^ n × 4

   (b)  Monthly

       A = P (1 + \frac{r}{2 * 100} ) ^ n × 2

   

   (c)  Annually

       A = P (1 + \frac{r}{100} ) ^ n

3 0
3 years ago
Suppose 12% of students are veterans. From a sample of 263 students, how unusual would it be to have less than 22 veterans?
kkurt [141]

Answer:

Yes, both np and n(1-p) are ≥ 10

Mean = 0.12 ; Standard deviation = 0.02004

Yes. There is a less than 5% chance of this happening by random variation. 0.034839

Step-by-step explanation:

Given that :

p = 12% = 0.12 ;

Sample size, n = 263

np = 263 * 0.12 = 31.56

n(1 - p) = 263(1 - 0.12) = 263 * 0.88 = 231.44

According to the central limit theorem, distribution of sample proportion approximately follow normal distribution with mean of p = 0.12 and standard deviation sqrt(p*(1 - p)/n) = sqrt (0.12 *0.88)/n = sqrt(0.0004015) = 0.02004

Z = (x - mean) / standard deviation

x = 22 / 263 = 0.08365

Z = (0.08365 - 0.12) / 0.02004

Z = −1.813872

Z = - 1.814

P(Z < −1.814) = 0.034839 (Z probability calculator)

Yes, it is unusual

0.034 < 0.05 (Hence, There is a less than 5% chance of this happening by random variation.

7 0
3 years ago
I need help with this someone please help
choli [55]

Answer:

0,-2,-8,-36

Step-by-step explanation:

6 0
3 years ago
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