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Alisiya [41]
3 years ago
13

PLEASE HELP ASAP!!! GIVING BRAINLIEST!!!!!!

Mathematics
2 answers:
beks73 [17]3 years ago
5 0

Answer:

A) 2 units

B) yes

For A) |5-3|=|2|=2 is the distance from his house to school.

For B)

The distance from his house to school is 2 units; the distance from school to the grocery store is |3--9|=|12|=12.  The total distance is 2+12 = 14.

The distance from his house to school is 2 units; the distance from school to the community center is |-4-6|=|-10|=10.  The total distance is 2+10 = 12.

The distance from the house to the school to the grocery store is greater.

Step-by-step explanation:

bekas [8.4K]3 years ago
4 0
Part A: 6 units
(Since 9 - 3 = 6)

Part B: Yes
The distance from the house to the school to the grocery store is 6 + 10 which is 16.
The distance from the house to the school to the community center is 6 + 5 which is 11
16 is greater than 11

If you have any questions on how I solved this feel free to comment :)
You might be interested in
Mario was making cookies. He mixed 2½ cups of flour, 1¼ cups of sugar and ½ cup of brown sugar together in a bowl. How many cups
STatiana [176]

Answer:

4 1/4

Step-by-step explanation:

2 1/2 + 1 1/4 + 1/2 = 5/2 + 5/4 + 1/2

LCM = 4

5/2 x 2/2 = 10/4

5/4 = 5/4

1/2 x 2/2 = 2/4

10/4 + 5/4 + 2/4 = 17/4

                          = 4 1/4

Therefore he put 4 1/4 cups altogether.

7 0
3 years ago
I just drew a blank can someone please help
PIT_PIT [208]

Answer:

≈ 542,029 copies

Step-by-step explanation:

37,400 copies represents a 6.9% of the total copies sold to date.

Therefore; Copies sold to date will be 100%

Thus;

Total number of copies sold = (37,400/6.9)× 100

                                               = 542,028.99 copies

                                               <u>≈ 542029 copies</u>

3 0
3 years ago
Read 2 more answers
Solve for x. Show the equation you used and your work.
IgorC [24]
Here, You need to apply "Proportionality Theorem"
According to this theorem, the ratio of components of a leg would be equal to the ratio of corresponding components of another leg.

In mathematical form, 
TV/VS = TW/WU

Substitute their values, 
14/6 = 21/(x+4)
14(x+4) = 21*6
14x+56 = 126
14x = 126-56
x = 70/14
x = 5

In short, Your Answer would be 5

Hope this helps!
4 0
3 years ago
The mathematics department of a college has 15 male professors, 9 female professors, 6 male teaching assistants, and 12 female t
Vesnalui [34]

Given:

The number of male professors = 15.

The number of female professors = 9.

The number of male teaching assistants = 6.

The number of female teaching assistants = 12.

A person is selected randomly from the group.

Required:

We need to find the probability that the selected person is a professor or a male.

Explanation:

The total number of people in the group = 15+9+6+12 = 42

n(S) =The total number of people in the group

n(S)=42

Let A be the event that the selected person is a professor or a male.

The number of people who are professors or male = 15+9+6 = 30

n(A)= The number of people who are professors or male.

n(A)=30

Let P(A) be the probability that the selected person is a professor or a male.

P(A)=\frac{n(A)}{n(S)}P(A)=\frac{30}{42}P(A)=\frac{15}{21}=\frac{5}{7}

Final answer:

The probability that the selected person is a professor or a male is 5/7.

7 0
2 years ago
Someone answer. Will give brainlest
Leto [7]

Area inside the semi-circle and outside the triangle is  (91.125π - 120) in²

Solution:

Base of the triangle = 10 in

Height of the triangle = 24 in

Area of the triangle = \frac{1}{2} bh

                                $=\frac{1}{2} \times 10\times24

Area of the triangle = 120 in²

Using Pythagoras theorem,

\text{Hypotenuse}^2=\text{base}^2+\text{height}^2

\text{Hypotenuse}^2=10^2+24^2

\text{Hypotenuse}^2=100+576

\text{Hypotenuse}^2=676

Taking square root on both sides, we get

Hypotenuse = 23 inch = diameter

Radius = 23 ÷ 2 = 11.5 in

Area of the semi-circle = \frac{1}{2}\pi r^2

                                      $=\frac{1}{2} \pi \times (13.5)^2

Area of the semi-circle = 91.125π in²

Area of the shaded portion = (91.125π - 120)  in²

Area inside the semi-circle and outside the triangle is  (91.125π - 120)  in².

5 0
3 years ago
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