All categories

3 years ago

Which of the following is not a possible value of x? A. -0.2 B. 0 C. 1 D. 3

Mathematics

2 answers:

anygoal [31]3 years ago

5 0

Answer:

Option D. 3

Step-by-step explanation:

For all the given options, let's substitute these values and check what length do they give for 5x+3.

A) -0.2:

5x+3 = 5 (-0.2) + 3 = 2

B) 0:

5x+3 = 5 (0) + 3 = 3

C) 1:

5x+3 = 5 (1) + 3 = 8

D) 3:

5x+3 = 5(3) + 3 = 18

So in my opinion, the option D. 3 cannot be possible value for x. The reason being that 3 gives us a length of 18 which is already shown in the diagram as the longest length.

While 5x+3 looks way smaller than the one shown by 18.

Vinvika [58]3 years ago

3 0

-0.2 is not a possible value of x because lengths cannot be negative.

You might be interested in

How to find x and y I dont understand

lesantik [10]

68= 4x-2+30 (notice they are vertical angles)
68= 4x+28
40=4x
10=x

68+y= 180 (forms a straight angle)
y=112

Final answer: x=10, y=112

4 0

2 years ago

Read 2 more answers

3x^2+kx=-3 What is the value of K will result in exactly one solution to the equation?

Scorpion4ik [409]

Answer:

For k = 6 or k = -6, the equation will have exactly one solution.

Step-by-step explanation:

Given a second order polynomial expressed by the following equation:

$ax^{2} + bx + c, a\neq0$ .

This polynomial has roots $x_{1}, x_{2}$ such that $ax^{2} + bx + c = (x - x_{1})*(x - x_{2})$ , given by the following formulas:

$x_{1} = \frac{-b + \sqrt{\bigtriangleup}}{2*a}$

$x_{2} = \frac{-b - \sqrt{\bigtriangleup}}{2*a}$

$\bigtriangleup = b^{2} - 4ac$

If $\bigtriangleup = 0$ , the equation has only one solution.

In this problem, we have that:

$3x^{2} + kx + 3 = 0$

$a = 3, b = k, c = 3$

$\bigtriangleup = b^{2} - 4ac$

$\bigtriangleup = k^{2} - 4*3*3$

$\bigtriangleup = k^{2} - 36$

We will only have one solution if $\bigtriangleup = 0$ . So

$\bigtriangleup = 0$

$k^{2} - 36 = 0$

$k^{2} = 36$

$k = \pm \sqrt{36}$

$k = \pm 6$

For k = 6 or k = -6, the equation will have exactly one solution.

3 0

2 years ago

Which is an asymptotic of the graph of the function y=cot [x- 2pi/3]

astraxan [27]

Answer:

Step-by-step sexplanations

yourmomhot

5 0

2 years ago

Determine the values of \theta if sec\;\theta=-\frac{2}{\sqrt{3}}.

Masja [62]

Answer:

See below.

Step-by-step explanation:

So, we have:

$\sec(\theta)=-2/\sqrt{3}$

Recall that secant is simply the reciprocal of cosine. So we can:

$\cos(\theta)=(\sec(\theta))^{-1}=(-2/\sqrt{3})^{-1}\\\cos(\theta)=-\sqrt{3}/2$

Now, recall the unit circle. Since cosine is negative, it must be in Quadrants II and/or III. The numerator is the square root of 3. The denominator is 2. The whole thing is negative. Therefore, this means that 150 or 5π/6 is a candidate. Therefore, due to reference angles, 180+30=210 or 7π/6 is also a candidate.

Therefore, the possible values for theta is

5π/6 +2nπ

and

7π/6 + 2nπ

6 0

2 years ago

PLSS HELP IMMEDIATELY!!! i’ll give brainiest if u don’t leave a link!

Zielflug [23.3K]

Answer: Evaluate the findings to compare to his hypothesis

Step-by-step explanation: Since the biologist already has the findings and has a hypothesis, he now has to compare both of them together.

3 0

2 years ago

Read 2 more answers