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erik [133]
3 years ago
8

Simplify the radical expression

Mathematics
1 answer:
iris [78.8K]3 years ago
5 0

Answer:

Step-by-step explanation:

\sqrt[4]{625x^{12}y^{8}}=\sqrt[4]{5*5*5*5*x^{3*4}y^{2*4}}\\\\ =\sqrt[4]{5^{4}*(x^{3})^{4}*(y^{2})^{4}}\\\\ =5*x^{3}*y^{2}\\\\=5x^{3}y^{2}

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Answer:

Step-by-step explanation:

\frac{QT}{Q'T'}=\frac{1}{2}\\

Scale factor:

1:2

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3 years ago
A coin is tossed two times. The set of outcomes is
dem82 [27]

Answer:

hey help me too lol

Step-by-step explanation:

its so importnt

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Use properties to evaluate 7/5(1/4 divide 7/4)(-10)
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3 years ago
In triangle RST, angle R is a right angle. If TR = 6 and TS = 8, what is the length of RS
lisabon 2012 [21]

Answer:

RS = 2\sqrt{7}

Step-by-step explanation:

Using Pythagoras' identity in the right triangle

RS² + RT² = TS² , that is

RS² + 6² = 8²

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RS² = 28 ( take the square root of both sides )

RS = \sqrt{28} = \sqrt{4(7)} = 2\sqrt{7} ≈ 5.3 ( to 1 dec. place )

8 0
3 years ago
I REALLY NEED HELP, ILL MEDAL!!!!
lara31 [8.8K]
Well, first of all, the first statement  (ABC = ADC) looks like it just says
that the two halves of the little square ... each side of the diagonal ...
are congruent.  That's no big deal, and it's no help in answering the
question.

The effect of the dilation is that all the DIMENSIONS of the square
are doubled ... each side of the square becomes twice as long.

Then, when you multiply (length x width) to get the area, you'd have

           Area = (2 x original length) x (2 x original width)

and that's
the same as      (2 x 2) x (original length x original width)

                        =     (4)  x  (original area) .


Here's an easy, useful factoid to memorize:

-- Dilate a line (1 dimension) by 'x' times . . . multiply the length by  x¹

-- Dilate a shape (2 dimensions) by 'x' . . . multiply area by  x²

-- Dilate a solid (3 dimensions) by 'x' . . . multiply volume by  x³

And that's all the dimensions we have in our world.
_______________________________

Oh, BTW . . .

-- Dilate a point (0 dimensions) by 'x' . . . multiply it by  x⁰  (1)

5 0
3 years ago
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