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3 years ago

10

What are 2 things that would make conditions more favorable for a disease to exist and be spread?

1 answer:

vazorg [7]3 years ago

4 0

Answer

1. The increase of social gatherings.{A lot of people coming together in one place like school}

2. People not quarantining themselves from the outside world when they are sick

Explanation:

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Which of the following values displays the pH of an acid? <br> A. 3<br> B. 12

tester [92]

A pH of 7 or lower makes something an acid so it would be 3

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3 years ago

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Hydrogen and oxygen make up water, which is a covalent compound. Which statement accurately describes hydrogen and oxygen? Hydro

alexdok [17]

hydrogen and oxygen are both nonmetals

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4 years ago

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Lorek lives near the North Pole. The snow in his backyard adds water to the atomosphere through______.

Elis [28]

Hello :))

Your question was:Lorek lives near the North Pole. The snow in his backyard adds water to the atomosphere through______.
The answer is: Sublimation

Hope this helps!
Good day! :D

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3 years ago

Is oxygen a necessary reactant for oxidation reaction

storchak [24]

Answer:

Oxidation: A process in which an atom loses an electron and therefore increases its oxidation number. ... So oxidation reactions need not involve oxygen. This redox reaction is actually the sum of two separate half-reactions (a reduction half-reaction and an oxidation half-reaction).

Explanation:

Hope this helped!

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3 years ago

A solution contains 1.817 mg of CoSO4 (155.0 grams/mole) per mL. Calculate the volume (in mL) of 0.009795 M Zn2 needed to titrat

Nana76 [90]

Answer:

<u> </u><u>85.952 ml</u> $Zn^2^+$ needed to titrate the excess complexing reagent .

Explanation:

Lets calculate

After addition of 80 ml of EDTA the solution becomes = 20 + 70 = 90 ml

As the number of moles of $CoSO_4$ = $\frac{Given mass }{molar mass}$

= $\frac{1.817}{155}$

=0.01172

Molarity = $\frac{no. of moles}{volume of solution}$

= $\frac{0.01172}{20}$

=0.000586 moles

Excess of EDTA = concentration of EDTA - concentration of CoSO4

= 0.009005 - 0.000586

= 0.008419 M

As M1V1 ( Excess of EDTA ) = M2V2 $(Zn^2^+)$

$0.008419\times100ml=0.009795\times V2$

$V2=\frac{0.008419\times100}{0.009795}$

V2 =85.952 ml

Therefore , <u>85.952 ml </u> $Zn^2^+$ needed to titrate the excess complexing reagent .

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3 years ago