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Anvisha [2.4K]
3 years ago
13

A gaseous mixture contains 434.0 Torr H 2 ( g ) , 434.0 Torr H2(g), 389.9 Torr N 2 ( g ) , 389.9 Torr N2(g), and 77.9 Torr Ar (

g ) . 77.9 Torr Ar(g). Calculate the mole fraction, χ , χ, of each of these gases.
Chemistry
1 answer:
weqwewe [10]3 years ago
8 0

Answer:

H₂: 0.48,  N₂: 0.43;  Ar: 0.09

Explanation:

First of all, sum all the pressures to know the total pressure in the mixture.

434 Torr + 389.9 Torr + 77.9 Torr = 901.8 Torr

Mole fraction = Pressure gas / Total Pressure

Mole Fraction H₂: 434 Torr /901.8 Torr = 0.48

Mole Fraction N₂: 389.9 /901.8 Torr =0.43

Mole Fraction Ar:  77.9 /901.8 Torr = 0.09

Remember: <u>SUM OF MOLE FRACTION = 1</u>

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Step 1

% by mass:

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Step 2

Procedure:

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<em>Answer:</em>

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Please see attachment. The resonance contributor are given.


Download docx
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