Answer:
66.72
Step-by-step explanation:
hope it help you
Answer:
The measure of arc EF = 41°
Step-by-step explanation:
Given:
Arc DE = 73°
![\angle FED=123\°](https://tex.z-dn.net/?f=%5Cangle%20FED%3D123%5C%C2%B0)
Now, we know from central angle theorem that the measure of central angle by an arc is twice that of the angle made by the same arc at the circumference. Therefore,
![\textrm{Major Arc DGF}=2\times \angle FED\\\textrm{Major Arc DGF}=2\times 123\\\textrm{Major Arc DGF}=246\°](https://tex.z-dn.net/?f=%5Ctextrm%7BMajor%20Arc%20DGF%7D%3D2%5Ctimes%20%5Cangle%20FED%5C%5C%5Ctextrm%7BMajor%20Arc%20DGF%7D%3D2%5Ctimes%20123%5C%5C%5Ctextrm%7BMajor%20Arc%20DGF%7D%3D246%5C%C2%B0)
Now, we know that sum of all arcs on a circle is equal to 360°.
Therefore, arc DGF + arc DE + arc EF = 360°
![246+73+arc\ EF=360\\319+arc\ EF=360\\arc\ EF=360-319=41\°](https://tex.z-dn.net/?f=246%2B73%2Barc%5C%20EF%3D360%5C%5C319%2Barc%5C%20EF%3D360%5C%5Carc%5C%20EF%3D360-319%3D41%5C%C2%B0)
Therefore, the measure of the arc EF is 41°.
Answer:
12 months=1 years
24 months=2 years
36 months=3 years
(click choose and pin the photo please) so that i can see options
hope it helps you
make me brainliest plz
Answer:
c.) No, because Cp < 1
Step-by-step explanation:
Let us assume that there is centered in the process
and, the width is 2 times the specification
So, the width is
![= 2 \times 0.07](https://tex.z-dn.net/?f=%3D%202%20%5Ctimes%200.07)
= 0.14
Now capability index = Cp is
![= \frac{specification\ width}{6 \times standard\ deviation}\\\\= \frac{0.14}{6\times 0.04}](https://tex.z-dn.net/?f=%3D%20%5Cfrac%7Bspecification%5C%20width%7D%7B6%20%5Ctimes%20standard%5C%20deviation%7D%5C%5C%5C%5C%3D%20%5Cfrac%7B0.14%7D%7B6%5Ctimes%200.04%7D)
= 0.58333
And the capability index should be minimum 1 for the process
And as we can see that Cp is 0.58333 which is less than 1 so the machine is not able to perform the job
Hene, the correct option is c.
Answer: The density of copper should be the same in a wire as it is in a chunk,
so the answer is 8.9 g/cm3.