Answer: -
5 : 1 : 3
Explanation: -
Mass of CO₂ = 2.2 g
Molar mass of CO₂ = 44 g / mol
Number of moles of CO₂ = 
= 
= 0.05 mol
Number of atoms of nitrogen = 6.02 x 10²¹
Number of moles of nitrogen = 
= 
= 0.01 mol
0.03 gram atom of sulphur means 0.03 moles of sulphur.
Thus the mole ratio of CO₂ : N : S = 0.05 : 0.01 : 0.03
= 5 : 1 : 3
Answer:
A.
Explanation:
The β-sheet is a twisted pattern in which the protein strands are laterally linked through hydrogen bonds. These β-sheet motifs are segments of 3 to 10 amino acids that are specially configured to form beta antiparallel strands. In β-sheet regions, the hydrogen bonds are localized among carbonyl and amino groups of the polypeptide backbone, and side chains (i.e., the R groups) are extended up and down in the plane of the β-sheet.
Answer:
pH= 9.2
Explanation:
Henderson hasselbach equation
pKa= log Ka= log (4.9 x 10^-10)=9.3
![pH=Pka+log \frac{[A-]}{[HA]}](https://tex.z-dn.net/?f=pH%3DPka%2Blog%20%5Cfrac%7B%5BA-%5D%7D%7B%5BHA%5D%7D)
![pH=9.3+log \frac{[CN-]}{[HCN]}](https://tex.z-dn.net/?f=pH%3D9.3%2Blog%20%5Cfrac%7B%5BCN-%5D%7D%7B%5BHCN%5D%7D)
![pH=9.3+log \frac{[0.64 M]}{[0.83 M]}](https://tex.z-dn.net/?f=pH%3D9.3%2Blog%20%5Cfrac%7B%5B0.64%20M%5D%7D%7B%5B0.83%20M%5D%7D)
pH= 9.2
The amount of heat that could be removed by 20.0 g of ethyl chloride is 8.184 kJ.
<h3>How do we calculate required heat?</h3>
Required amount of heat which can be removed for the vaporization will be calculated as:
Q = (n)(ΔHv), where
- n = moles of ethyl chloride
- ΔHv = heat of vaporization = 26.4 kj/mol
Moles will be calculated as:
n = W/M, where
- W = given mass of ethyl chloride = 20g
- M = molar mass of ethyl chloride = 64.51 g/mol
n = 20 / 64.51 = 0.31 mol
On putting all these values in the above equation, we get
Q = (0.31)(26.4) = 8.184 kJ
Hence involved amount of heat is 8.184 kJ.
To know more about heat of vaporization, visit the below link:
brainly.com/question/13106213
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