New initial velocity=59.1(5)=295.5m/s
We will use proportions to find the distance.




A car is traveling due north at 23.6 m>s.
Find the velocity of the car after 7.10 s if its
acceleration is
The acceleration is known to be: a(t) = 1.7 m/s2.
We must integrate over time to obtain the velocity function, and the results are:
v(t) = (1.7m/s^2)
*t + v0
If we suppose that we begin at 23.6 m/s, then the initial velocity is: v0 = 23.6 m/s, where v0 is the beginning velocity.
The velocity formula is then: v(t) = (1.7m/s2).
*t + 23.6 m/s
We now seek to determine the value of t such that v(t) = 27.8 m/s.
Consequently, v(t) = 27.8 m/s = (1.7 m/s2)
*t + 23.6 m/s = (1.7 m/s2) 27.8 m/s - 23.6 m/s
t = 2.5 seconds when *t 4.2 m/s = (1.7 m/s/2)
At such acceleration, 2.5 seconds are required.
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Answer:
Where is question 12, we need it to answer this question
Explanation:
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The skier's speed at time <em>t</em> is
<em>v</em> = (23 m/s²) <em>t</em>
To reach a speed of 9.3 m/s, the skier would need
9.3 m/s = (23 m/s²) <em>t</em>
<em>t</em> = (9.3 m/s) / (23 m/s²)
<em>t</em> ≈ 0.404 s