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shutvik [7]
3 years ago
7

qual charges, one at rest, the other having a velocity of 104 m/s, are released in a uniform magnetic field. Which charge has th

e largest force exerted on it by the magnetic field?

Physics
1 answer:
Yakvenalex [24]3 years ago
4 0

Answer:

The correct option is D

Explanation:

From the question we are told that

    The speed of the first charge is  v  = 0 \ m/s

This is because it is at rest

     The speed of the second charge is  v  =  10^{4} \ m/s

Generally the force exerted by a magnetic field on a charge is mathematically represented as

      F_q  =  q * v  *  B sin \theta

Now looking at this above equation we can see that F_q can only be maximum at  \theta  =  90 ^o and this only obtained when the direction of the charge (i.e its velocity  ) is perpendicular to the direction of the magnetic field

so the correct option for this question is D

     

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Answer:

The sound level of the 26 geese is  Z_{26}= 96.15 dB

Explanation:

From the question we are told that

    The  sound level is Z_1 =  81.0 \ dB

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Generally the intensity level of sound is mathematically represented as

        The intensity of sound level in dB  for one  goose is mathematically represented as

                       Z_1 = 10 log [\frac{I}{I_O} ]

Where I_o is the  threshold level of intensity with value  I_o = 1*10^{-12} \  W/m^2

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For 26 geese the intensity would be  

          I_{26} = 26 * I

   Then  the intensity of 26 geese in dB is  

              Z_{26} = 10 log[\frac{26 I }{I_o} ]

               Z_{26} = 10 log (\ \ 26 *  [\frac{ I }{I_o} ]\ \ )

               Z_{26} = 10 log (\ \ 26  \ \ ) *   (\ \  10 log [\frac{ I }{I_o} ]\ \ )

 From the law of logarithm we have that

              Z_{26} = 10 log 26 +  10 log [\frac{I}{I_0} ]

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