qual charges, one at rest, the other having a velocity of 104 m/s, are released in a uniform magnetic field. Which charge has th
e largest force exerted on it by the magnetic field?
1 answer:
Answer:
The correct option is D
Explanation:
From the question we are told that
The speed of the first charge is
This is because it is at rest
The speed of the second charge is
Generally the force exerted by a magnetic field on a charge is mathematically represented as
Now looking at this above equation we can see that can only be maximum at
and this only obtained when the direction of the charge (i.e its velocity ) is perpendicular to the direction of the magnetic field
so the correct option for this question is D
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Answer:
D. n=6 to n=2
Explanation:
Given;
energy of emitted photon, E = 3.02 electron volts
The energy levels of a Hydrogen atom is given as; E = -E₀ /n²
where;
E₀ is the energy level of an electron in ground state = -13.6 eV
n is the energy level
From the equation above make n, the subject of the formula;
n² = -E₀ / E
n² = 13.6 eV / 3.02 eV
n² = 4.5
n = √4.5
n = 2
When electron moves from higher energy level to a lower energy level it emits photons;
For a photon to be emitted, electron must move from higher energy level to a lower energy level. The higher energy level is 6 while the lower energy level is 2
Therefore, The electron energy-level transition is from n = 6 to n = 2