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Pavel [41]
3 years ago
10

State the radius of the circle of the equation

Mathematics
1 answer:
Eva8 [605]3 years ago
5 0

Answer:

radius = √5 = 2.24 to nearest hundredth.

Step-by-step explanation:

(x + 3)^2 + (y + 3)^2 = 5   comparing with the standard form

(x - h)^2 + (y - k)^2 = r^2

-h = 2 so h = -3,  -k = 3  so k = -3.

r^2 = 5 so r = √5.

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Someone do this got me rq
skelet666 [1.2K]

Answer:

The last listed functional expression:

\left \{ {x+1\,\,\,\,{x\geq 2} \atop {x+2 \,\,\,\,x

Step-by-step explanation:

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It is also important to understand that the "solid" dot that is located in the region where the domain changes, (x=2) belongs to the domain on the right hand side of the graph, So, we are looking for a function definition that contains x+1 for the function, for the domain: x\geq 2.

Such definition is the one given last (bottom right) in your answer options.

\left \{ {x+1\,\,\,\,{x\geq 2} \atop {x+2 \,\,\,\,x

7 0
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The correct answer is zero.

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