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Andrei [34K]
3 years ago
15

If both pairs of opposite angles of a quadrilateral are supplemental then the quadrilateral is a parallelogram

Mathematics
1 answer:
Nutka1998 [239]3 years ago
8 0

Answer:

THEOREM: If a quadrilateral has consecutive angles which are supplementary, then it is a parallelogram. BRAINLIEST LOL :)

Step-by-step explanation:

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Explain how you can use doubles when multiplying with 4 to find 4x8
hoa [83]
When multiplying by 4, you can simply multiply it by 2 twice (prime factorization).
In this example-
4 times 8 = 32
2 times 2 times 8 = 32

Hope this helped!
By the way, I'm getting closer to leveling up, so if you liked my answer, you could reward me with brainliest answer. That'd be great!
8 0
3 years ago
You want to estimate the number of students in a junior high school who ride the school bus. which sample is unbiased?​
Vika [28.1K]

Answer:

Option B - 90 students at random during lunch

Step-by-step

An unbiased sample is defined as:

A sample is an unbiased sample if every individual or the element in the population has an equal chance of being selected.

Based on this, we can eliminate:

Option A) - It prevents non-eighth-graders of the school from being represented.

Option C) - Students in a hallway might take a particular class together/may be of the same grade. This gives them an unfair advantage.

Option D) - All students who are not in chorus are not represented in this set.

8 0
3 years ago
Can anyone help me with primary 5 hw ?
Illusion [34]
B) 28×50, then take the answer - 1100
5 0
3 years ago
EXPLAIN why we placed the value of x= 4/3( the minimum value) into the equ of gradient(dy/dx) [in the answer, marking scheme att
aliina [53]
y=x(x-2)^2
\implies y'=(x-2)^2+2x(x-2)=3x^2-8x+4=(3x-2)(x-2)=0
\implies x=\dfrac23,x=2

are the critical points, and judging by the picture alone, you must have b=\dfrac23 and a=2. (You might want to verify with the derivative test in case that's expected.)

Then the shaded region has area

\displaystyle\int_0^2x(x-2)^2\,\mathrm dx=\dfrac43

I'll leave the details to you.

Now, for part (iv), you're asked to find the minimum of \dfrac{\mathrm dy}{\mathrm dx}=y', which entails first finding the second derivative:

y'=3x^2-8x+4
\implies y''=6x-8

setting equal to 0 and finding the critical point:

6x-8=0\implies x=\dfrac86=\dfrac43

This is to say the minimum value of \dfrac{\mathrm dy}{\mathrm dx} *occurs when x=\dfrac43*, but this is not necessarily the same as saying that \dfrac43 is the actual minimum value.

The minimum value of \dfrac{\mathrm dy}{\mathrm dx} is obtained by evaluating the derivative at this critical point:

m=\dfrac{\mathrm dy}{\mathrm dx}\bigg|_{x=4/3}=3\left(\dfrac43\right)^2-8\left(\dfrac43\right)+4=-\dfrac43
4 0
4 years ago
Pleeeeeeeeese help quik
Ilya [14]

Answer:

#3

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
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