What is the approximate perimeter of a rhombus with the diagonals that measure 12 feet and 18 feet

Mathematics

1 answer:

Fynjy0 [20]3 years ago

7 0

Answer:

The perimeter of a rhombus with diagonals of 12 feet and 18 feet would be 60 feet.

Step-by-step explanation:

Perimeter of a rhombus: S1 + S2 + S3 + S4 = answer. (S stands for side.)

12 ft. + 18 ft. + 12 ft. + 18 ft. = 60 ft.

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Is anyone able to answer this for me? GIVING BRAINLIEST! hurry!

svetoff [14.1K]

Nicoles pattern:

1
5
17
53
161

Ian’s pattern:

0
1
3
7
15

Ordered pair:

(1, 0)
(5, 1)
(17, 3)
(53, 7)
(161, 15)

Table 1 -

Sequence 1:

9
11
13
15
17

Sequence 2:

5
8
11
14
17

Ordered pair:

(9, 5)
(11, 8)
(13, 11)
(15, 14)
(17, 17)

Table 2 -

Sequence 1:

20
16
12
8
4

Sequence 2:

20
17
14
11
8

Ordered pair:

(20, 20)
(16, 17)
(12, 14)
(8, 11)
(4, 8)

Table 3 -

Sequence 1:

1
3
7
15
31

Sequence 2:

40
24
16
12
10

Ordered pair:

(1, 40)
(3, 24)
(7, 16)
(15, 12)
(31, 10)

5 0

2 years ago

Will give brainliest answer

olganol [36]

Answer:

Step-by-step explanation:

Area of a big right triangle = 1/2 * 4 * (2+2+6) = 1/2 * 4 *10 =20

Area of a left right triangle = 1/2* 2*2 = 2

Area of a right right triangle = 1/2 * 6*2 =6

Area of a square = 2*2 = 4

All together:

20+ 2+6+4 =32