Step-by-step explanation:
In order to describe speed of an object, we must describe the average speed of the entire trip. It is equal to the distance moved divided by time taken.
If a person covers a distance of 1 km to the library in 15 minutes, we can find its average speed.
Firstly, we convert 15 minutes to hour, 15 min = 0.25 hours
Now, using formula of speed = distance/time

It means that the average speed of the person is 4 km/h. Hence, the given statement is true.
Answer:
Is there supposed to be a attachment. because I dont see anything
Step-by-step explanation:
Leah, she ran farther by 1/21
How you get the answer:
5/7
Multiply 7x3 to get the denominator and do the same to the numerator 5x3! Which is 15/21
To get 21 from 2/3 is to multiply 3x7 (denominator) and 2x7 (numerator) to get 14/21
15/21 > 14/21 so Leah ran farther by 1/21
Answer:
See explanation
Step-by-step explanation:
Given:
![A=\left[\begin{array}{cc}-2&4\\1&3\end{array}\right]](https://tex.z-dn.net/?f=A%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D-2%264%5C%5C1%263%5Cend%7Barray%7D%5Cright%5D)
![B=\left[\begin{array}{cc}-2&1\\3&7\end{array}\right]](https://tex.z-dn.net/?f=B%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D-2%261%5C%5C3%267%5Cend%7Barray%7D%5Cright%5D)
A. Find AB:
![AB=\left[\begin{array}{cc}-2&4\\1&3\end{array}\right]\cdot \left[\begin{array}{cc}-2&1\\3&7\end{array}\right]=\left[\begin{array}{cc}-2\cdot (-2)+4\cdot 3&-2\cdot 1+4\cdot 7\\1\cdot (-2)+3\cdot 3&1\cdot 1+3\cdot 7\end{array}\right]=\left[\begin{array}{cc}16&26\\7&22\end{array}\right]](https://tex.z-dn.net/?f=AB%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D-2%264%5C%5C1%263%5Cend%7Barray%7D%5Cright%5D%5Ccdot%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D-2%261%5C%5C3%267%5Cend%7Barray%7D%5Cright%5D%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D-2%5Ccdot%20%28-2%29%2B4%5Ccdot%203%26-2%5Ccdot%201%2B4%5Ccdot%207%5C%5C1%5Ccdot%20%28-2%29%2B3%5Ccdot%203%261%5Ccdot%201%2B3%5Ccdot%207%5Cend%7Barray%7D%5Cright%5D%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D16%2626%5C%5C7%2622%5Cend%7Barray%7D%5Cright%5D)
B. Find BA:
![BA=\left[\begin{array}{cc}-2&1\\3&7\end{array}\right]\cdot \left[\begin{array}{cc}-2&4\\1&3\end{array}\right]=\left[\begin{array}{cc}-2\cdot (-2)+1\cdot 1&-2\cdot 4+1\cdot 3\\3\cdot (-2)+7\cdot 1&3\cdot 4+7\cdot 3\end{array}\right]=\left[\begin{array}{cc}5&-5\\1&33\end{array}\right]](https://tex.z-dn.net/?f=BA%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D-2%261%5C%5C3%267%5Cend%7Barray%7D%5Cright%5D%5Ccdot%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D-2%264%5C%5C1%263%5Cend%7Barray%7D%5Cright%5D%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D-2%5Ccdot%20%28-2%29%2B1%5Ccdot%201%26-2%5Ccdot%204%2B1%5Ccdot%203%5C%5C3%5Ccdot%20%28-2%29%2B7%5Ccdot%201%263%5Ccdot%204%2B7%5Ccdot%203%5Cend%7Barray%7D%5Cright%5D%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D5%26-5%5C%5C1%2633%5Cend%7Barray%7D%5Cright%5D)
C. Answers are not the same
D. Matrices multiplication is not commutastive in general, so
