Answer:
1. 9 moles of sulphur.
2. 13 moles of SO3
3. 0.77 mole of AgCl.
Explanation:
1. The balanced equation for the reaction is given below:
2Fe + 3S —> Fe2S3
From the balanced equation above,
2 moles of Fe required 3 moles of S.
Therefore, 6 moles of Fe will require = (6 x 3)/2 = 9 moles of S.
Therefore, 9 moles of sulphur is required.
2. We'll begin by writing the balanced equation for the reaction. This is given below:
2SO2 + O2 —> 2SO3
From the balanced equation above,
2 moles of SO2 reacted to produce 2 moles of SO3.
Therefore, 13 moles of SO2 will also react to produce 13 moles of SO3.
Therefore, 13 moles of SO3 were produced from the reaction.
3. We'll begin by calculating the number of mole in 45g of NaCl. This is illustrated below:
Mass of nac= 45g
Molar mass of NaCl = 23 + 35.5 = 58.5g/mol
Number of mole of NaCl =..?
Mole = Mass /Molar Mass
Number of mole of NaCl = 45/58.5
Number of mole of NaCl = 0.77 mole
Next, we shall write the balanced equation for the reaction. This is given below:
NaCl + AgNO3 —> NaNO3 + AgCl
Now, we can obtain the number of mole of silver chloride, AgCl obtained from the reaction as follow:
From the balanced equation above,
1 mole of NaCl reacted to produce 1 mole of AgCl.
Therefore, 0.77 mole of NaCl will also react to produce 0.77 mole of AgCl.
Therefore, 0.77 mole of AgCl were obtained from the reaction.
