367.2 g of silver
Explanation:
To find the mass of a substance knowing the number of moles we use the following formula:
number of mole = mass / molecular weight
In the case of silver we use the atomic weight of 108 g/mole.
mass = number of moles × molecular weight
mass of silver = 3.4 moles × 108 g/mole
mass of silver = 367.2 g
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The balanced neutralization reaction here is:
Ca(OH)2 + 2HBr --> 2H2O + CaBr2
Notice that two moles of Her are required to neutralize every one mole of Ca(OH)2. This means that for however many moles of Her reacted, HALF as many moles of Ca(OH)2 reacted as well.
Moles of HBr reacted = 0.75 M x 0.345 L = 0.259 mol
Moles of Ca(OH)2 reacted = 0.259 mol / 2 = 0.130 mol
Concentration of Ca(OH)2 = 0.130 mol / 0.250 L = 0.52 M