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3 years ago

An atom contains 4 protons, 3 neutrons, and 5 electrons. what is its total electric charge?

Chemistry

2 answers:

Daniel [21]3 years ago

4 0

Answer:

The charge will be "-1".

Explanation:

In a neutral atom there are protons and neutrons in the nucleus and the same number of electrons (as of protons) in the outer shells.

As given that there are four protons and 5 electrons, it means the given atom is not neutral.

An atom may have lesser number of electrons than that of protons or it may have more number of electrons.

If an atom has less number of electrons, it will carry positive charge

If an atom has more number of electrons, it will carry negative charge.

So the total electric charge on the atom will be "-1"

Rashid [163]3 years ago

3 0

Neutrons are uncharged
proton (+4) + electrons (-5)= -1

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Answer:

The Atomic Number

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4 years ago

During the extraction of iron from iron oxide in the Blast Furnace state the function of limestone

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Answer:

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3 years ago

Please help!!!!! I need the correct answer quickly!!!

xxMikexx [17]

Answer :

The oxidation state of oxygen (O) in $OF_2$ is, (+2)

The oxidation state of carbon (C) in $CO$ is, (+2)

The oxidation state of nitrogen (N) in $K_3N$ is, (-3)

Explanation :

Oxidation number : It represent the number of electrons lost or gained by the atoms of an element in a compound.

Oxidation numbers are generally written with the sign (+) and (-) first and then the magnitude.

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Rules for Oxidation Numbers :

The oxidation number of a free element is always zero.

The oxidation number of a monatomic ion equals the charge of the ion.

The oxidation number of Hydrogen (H) is +1, but it is -1 in when combined with less electronegative elements.

The oxidation number of oxygen (O) in compounds is usually -2, but it is -1 in peroxides.

The oxidation number of a Group 1 element in a compound is +1.

The oxidation number of a Group 2 element in a compound is +2.

The oxidation number of a Group 17 element in a binary compound is -1.

The sum of the oxidation numbers of all of the atoms in a neutral compound is zero.

The sum of the oxidation numbers in a polyatomic ion is equal to the charge of the ion.

(a) The given compound is, $OF_2$

Let the oxidation state of 'O' be, 'x'

$x+2(-1)=0\\\\x-2=0\\\\x=+2$

The oxidation state of oxygen (O) in $OF_2$ is, (+2)

(b) The given compound is, $CO$

Let the oxidation state of 'C' be, 'x'

$x+(-2)=0\\\\x-2=0\\\\x=+2$

The oxidation state of carbon (C) in $CO$ is, (+2)

(c) The given compound is, $K_3N$

Let the oxidation state of 'N' be, 'x'

$3(+1)+x=0\\\\3+x=0\\\\x=-3$

The oxidation state of nitrogen (N) in $K_3N$ is, (-3)

7 0

3 years ago

Read 2 more answers

A piece of radioactive radium is added to water.

Dafna1 [17]

Ra(s) + H₂O(g) → Ra(OH)₂ (aq) + H₂ (g)

<u>Explanation:</u>

Radioactive radium reacts easily with water produces radium hydroxide and hydrogen gas. In this reaction, Radium is sin solid state reacts with the water in the gaseous state to produces aqueous radium hydroxide and the hydrogen gas. This reaction occurs rapidly than in Barium. We can write this reaction as,

Radium(s) + water(g) → Radium hydroxide (aq) + Hydrogen (gas)

This can be represented using the symbols as,

Ra(s) + H₂O(g) → Ra(OH)₂ (aq) + H₂ (g)

Thus the above process can be expressed with such chemical reaction.

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4 years ago