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muminat
3 years ago
7

How is electron movement related to covalent bonding in ammonia, NH3?

Chemistry
2 answers:
antoniya [11.8K]3 years ago
4 0

How is electron movement related to covalent bonding in ammonia, NH3?

A) Electrostatic sharing in a sea of electrons around the atoms allows bonds to form. 
B) The atomic orbitals overlap and electrons are shared between the atoms forming bonds. 
C) A transfer of electrons forms ions which are electrostatically attracted forming bonds. 
D) Orbital exchange occurs between the atoms to redistribute the electrons and form bonds.

The electron movement related to covalent bonding in ammonia, NH3 is The atomic orbitals overlap and electrons are shared between the atoms forming bonds. The answer is letter B.

IRINA_888 [86]3 years ago
3 0

Answer:

B

Explanation:

A) The sea of electrons only happen with metalic bond, a bond with two metalic elements.

B) As both elements in ammonia (N and H) are non-metals we don't observe an transfer of electrons, both elements share the number of electrons needed to stablize it (3 electrons for the N and 1 for the H).

C) To have a transfer of electrons, we need a bond between a metal and a non-metal, in this case, N and H are non-metals, so this doesn't happen.

D) The electrons are shared, only the electrons nothing happens between the orbitals.

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Answer:

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<u>Quick conversion chart of moles H2SO3 to grams</u>

1 moles H2SO3 to grams = 82.07908 grams

2 moles H2SO3 to grams = 164.15816 grams

3 moles H2SO3 to grams = 246.23724 grams

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5 moles H2SO3 to grams = 410.3954 grams

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10 moles H2SO3 to grams = 820.7908 grams

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Consider the nuclear equation below. Superscript 235 subscript 92 upper U right arrow superscript 4 subscript 2 upper H e. What
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\rm_{90}^{231}\text{Th}

Explanation:

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\rm _{92}^{235}\text{U} \longrightarrow \,  _{2}^{4}\text{He} + X

Let's write X as a nuclear symbol.

\rm _{92}^{235}\text{U} \longrightarrow \,  _{2}^{4}\text{He} + _{Z}^{A}\text{X}

The main point to remember in balancing nuclear equations is that the sums of the superscripts and of the subscripts must be the same on each side of the reaction arrow.

Then

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And your nuclear equation becomes

\rm _{92}^{235}\text{U} \longrightarrow \,  _{2}^{4}\text{He} +\, _{90}^{231}\text{X}

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6.0 moles of Na and 4.0 moles of Cl2 are mixed, how manu moles of NaCl in moles cane be made from this mixture
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Answer:

Moles of NaCl formed is 6.0 moles

Explanation:

We are given the equation;

2 Na(s) + Cl₂(g) → 2 NaCl(s)

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From the reaction;

2 moles of sodium reacts with 1 mole of chlorine gas to form 2 moles of NaCl

In this case;

6 moles of Na would require 3 moles of Cl₂, this means that chlorine gas is in excess.

Thus, the rate limiting reagent is sodium.

But, 2 moles of sodium reacts to form 2 moles of NaCl

Therefore;

Moles of NaCl = Moles of Na

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Thus, moles of sodium chloride produced is 6.0 moles

3 0
3 years ago
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