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muminat
3 years ago
7

How is electron movement related to covalent bonding in ammonia, NH3?

Chemistry
2 answers:
antoniya [11.8K]3 years ago
4 0

How is electron movement related to covalent bonding in ammonia, NH3?

A) Electrostatic sharing in a sea of electrons around the atoms allows bonds to form. 
B) The atomic orbitals overlap and electrons are shared between the atoms forming bonds. 
C) A transfer of electrons forms ions which are electrostatically attracted forming bonds. 
D) Orbital exchange occurs between the atoms to redistribute the electrons and form bonds.

The electron movement related to covalent bonding in ammonia, NH3 is The atomic orbitals overlap and electrons are shared between the atoms forming bonds. The answer is letter B.

IRINA_888 [86]3 years ago
3 0

Answer:

B

Explanation:

A) The sea of electrons only happen with metalic bond, a bond with two metalic elements.

B) As both elements in ammonia (N and H) are non-metals we don't observe an transfer of electrons, both elements share the number of electrons needed to stablize it (3 electrons for the N and 1 for the H).

C) To have a transfer of electrons, we need a bond between a metal and a non-metal, in this case, N and H are non-metals, so this doesn't happen.

D) The electrons are shared, only the electrons nothing happens between the orbitals.

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Answer:

19.488 kJ

Explanation:

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2Li+Cl_2+10H_2O ----->LiCl.10H_2O              -------- (2)

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LiCl.7H_2O ------>  Li + \frac{1}{2} Cl_2+7H_20             ---------- (4)

The overall reaction =

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The heat effects of the above reactions from 1-4 respectively are in the order ; 11311.34 kJ, -857.49 kJ, -873.61 kJ and 439.288kJ respectively

The overall enthalpy change is:

\delta H = \delta H _{LiCl.3H_2O}+\delta H_{3H_2O}  + \delta  H_{2(LiCl.5H_2O)} + \delta  H _{liCl.7H_2O}

\delta H =Q at constant pressure;

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