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muminat
3 years ago
7

How is electron movement related to covalent bonding in ammonia, NH3?

Chemistry
2 answers:
antoniya [11.8K]3 years ago
4 0

How is electron movement related to covalent bonding in ammonia, NH3?

A) Electrostatic sharing in a sea of electrons around the atoms allows bonds to form. 
B) The atomic orbitals overlap and electrons are shared between the atoms forming bonds. 
C) A transfer of electrons forms ions which are electrostatically attracted forming bonds. 
D) Orbital exchange occurs between the atoms to redistribute the electrons and form bonds.

The electron movement related to covalent bonding in ammonia, NH3 is The atomic orbitals overlap and electrons are shared between the atoms forming bonds. The answer is letter B.

IRINA_888 [86]3 years ago
3 0

Answer:

B

Explanation:

A) The sea of electrons only happen with metalic bond, a bond with two metalic elements.

B) As both elements in ammonia (N and H) are non-metals we don't observe an transfer of electrons, both elements share the number of electrons needed to stablize it (3 electrons for the N and 1 for the H).

C) To have a transfer of electrons, we need a bond between a metal and a non-metal, in this case, N and H are non-metals, so this doesn't happen.

D) The electrons are shared, only the electrons nothing happens between the orbitals.

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How many moles of NH3 would be formed from the complete reaction of 16.0 g H2?
natima [27]

Taking into account the reaction stoichiometry, 5.33 moles of NH₃ are formed from the complete reaction of 16 grams of H₂.

<h3>Reaction stoichiometry</h3>

In first place, the balanced reaction is:

N₂ + 3 H₂ → 2 NH₃

By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:

  • N₂: 1 mole
  • H₂: 3 moles
  • NH₃: 2 moles

The molar mass of the compounds is:

  • N₂: 14 g/mole
  • H₂: 2 g/mole
  • NH₃: 17 g/mole

Then, by reaction stoichiometry, the following mass quantities of each compound participate in the reaction:

  • N₂: 1 mole ×14 g/mole= 14 grams
  • H₂: 3 moles ×2 g/mole= 6 grams
  • NH₃: 2 moles ×17 g/mole=34 grams

<h3>Mass of NH₃ formed</h3>

The following rule of three can be applied: if by reaction stoichiometry 6 grams of H₂ form 2 moles of NH₃, 16 grams of H₂ form how many moles of NH₃?

moles of NH_{3}= \frac{16 grams of H_{2} x2moles of NH_{3}}{6 grams of H_{2}}

<u><em>moles of NH₃= 5.33 moles</em></u>

Then, 5.33 moles of NH₃ are formed from the complete reaction of 16 grams of H₂.

Learn more about the reaction stoichiometry:

brainly.com/question/24741074

brainly.com/question/24653699

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<h2>Answer:</h2><h3>Balanced equation:</h3>

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<h3>Description:</h3>

There should be 8 molecules of oxygen which react with 2 molecules of butane to produce 8 molecules of carbon dioxide and 10 molecules of water.


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